使用sql获取按小时分组的每日数据

Question

我有一个mysql表，其中有两列id和出勤时间，我想每小时选择count(id)。

id	出席时间
1	1725256398
2	1725258398
3	1725264581
4	1725277777
5	1725277777
6	1725277777
7	1725298931
8	1725299156
9	1725299156

我的预期结果是：

时间	计数
11:00	2
01:00	1
05:00	3
11:00	3

I have tried following query:-

SELECT 
    CONCAT(
        DATE(FROM_UNIXTIME(attendancetime)), ' ',
        LPAD(FLOOR(HOUR(FROM_UNIXTIME(attendancetime)) / 3) * 3, 2, '0'), ':00:00'
    ) AS TIME,
    count(id) AS COUNT
FROM operationallog
GROUP BY DATE(FROM_UNIXTIME(attendancetime)), FLOOR(HOUR(FROM_UNIXTIME(attendancetime)) / 3)
ORDER BY TIME;

请提供mysql查询来实现此结果

Answer 1

也许你需要

SELECT DATE_FORMAT(FROM_UNIXTIME(attendancetime), '%Y-%m-%d %H:00') date_time,
       COUNT(*) amount
FROM tablename
GROUP BY 1;

？