无法让它工作交互失败discord.js

问题描述 投票:0回答:1

我一直在编写一个不和谐的票证机器人,该机器人在用户打开票证后会打开一个私人频道,我还添加了一个运行良好的高级设置系统。但是,我无法弄清楚为什么机器人在单击“创建票证”按钮后没有创建票证(下面的视频展示)。我花了几个小时试图弄清楚但我无法解决任何问题。请帮忙。 代码如下:https://github.com/ScremerMemer/Advanced-Ticket-Bot

视频:https://www.youtube.com/watch?v=_6ZS_IC780c&ab_channel=Saket

node.js discord.js
1个回答
0
投票

以下代码即可完成这项工作。

     const ticketType = interaction.values[0]; 
     // We get the value of the select menu.

    const embed = new EmbedBuilder()
      .setTitle("New Ticket")
      .setColor("Green")
      .setDescription(`New ticket of type ‘${ticketType}’.`)

    interaction.guild?.channels.create({
        name: `${interaction.user.displayName}-ticket`,
        type: ChannelType.GuildText,
        permissionOverwrites: [
            {
                id: interaction.user.id,
                allow: [PermissionsBitField.Flags.ViewChannel],
            },
            {
                id: "roleId", // The role you want him to see this channel.
                allow: [PermissionsBitField.Flags.ViewChannel],
            },
            {
                id: interaction.guild.id,
                deny: [PermissionsBitField.Flags.ViewChannel],
            },
        ],
        parent: "categoryId", // Under which category the channel will open.
      }).then((channel) => {
        channel.send({
            content: `<@${interaction.user.id}>`,
            embeds: [embed]
        })
      })
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