我需要为一门课程写一个贷款程序,到目前为止,我有这样一段代码。
/*
Project: Course Project - Loan Calculator
Program Description: To calculate customer's loan
information including interest rate, monthly
payment and number of months payments will be
required for.
Developer: ___________
Last Update Date: June 1st, 2020
*/
#include <iostream>
#include <string>
//variables listed here
double loanAmt = 0, intRate = 0, loanLength = 0;
std::string CustName[0];
int choice; //menu choice identifier
using namespace std;
int main()
{
//Welcome User
cout << "Thank you for using our calculator." << endl;
cout << endl;
cout << "Please enter the number of your preferred calculator and press 'Enter': " << endl;
cout << endl;
cin >> choice;
{
while (choice !=4);
switch (choice)
{
case 1:
cout << "Monthly Payment Calculator:";
cout << endl;
break;
case 2:
cout << "Interest Rate Calculator:";
cout << endl;
break;
case 3:
cout << "Payment Term (In Months):";
cout << endl;
case 4:
cout << "Exit Calculator:";
default: //all other choices
cout << "Please Select A Valid Option.";
break;
}
}
}
我试着把cin << choice; 移到很多不同的地方,包括为开关写的while循环里面,但我似乎只能让它显示菜单的提示,但不能显示菜单选项本身,而且它不接受输入。如果有区别的话,我是第一次使用Xcode,我需要它在那里运行,因为我不能在我的Visual studio(Mac)版本上运行C++。我可能在哪里出了问题,任何关于为什么我的版本是错误的见解都会被感激,因为我仍然是非常新的编码整体。谢谢你。
你有这个。
while (choice !=4);
这使得你的代码永远不会超过这个while循环的范围 除非你的编译器在优化过程中删除了这一行。
这才是正确的方法。
while (choice !=4) {
switch (choice)
{
case 1:
cout << "Monthly Payment Calculator:";
cout << endl;
break;
case 2:
cout << "Interest Rate Calculator:";
cout << endl;
break;
case 3:
cout << "Payment Term (In Months):";
cout << endl;
case 4:
cout << "Exit Calculator:";
default: //all other choices
cout << "Please Select A Valid Option.";
break;
}
cin >> choice; // have it right after the switch
}