我想做的是创建QTableView的子类,该子类将接受标准化模型(这是mysql查询的结果),并填充它。有了它,我想定义一个自定义上下文菜单,该菜单允许我添加或删除行。这种方法允许我一次定义模型和子类,然后将它们都调用,以使用许多不同的查询填充它们,而无需重复代码。
add_row
和remove_row
QAction本质上将调用模型方法insertRows
和removeRows
。
这是一个起作用的示例(除了独立的mariadb模块:
from PySide2 import QtWidgets, QtCore, Qt, QtGui
import maria_db
import numpy
app = QtWidgets.QApplication([])
#Define model for tablePersonnel
class TableModel(QtCore.QAbstractTableModel):
def __init__(self, db,query,tableName,id):
super(TableModel, self).__init__()
self.db=db
self.query=query
self.tableName=tableName
self.id=id
self.pullData()
def pullData(self):
self.datasheet=self.db.RunQuery(self.query)
self.rows = numpy.array(self.datasheet.fetchall())
self.headers = numpy.array(self.datasheet.column_names)
self.idIndex=int(numpy.where(self.headers==self.id)[0])
def data(self, index, role):
if role == QtCore.Qt.DisplayRole:
return str(self.rows[index.row()][index.column()])
def rowCount(self, parent):
return len(self.rows)
def columnCount(self, parent):
return len(self.headers)
def headerData(self, section, orientation, role=QtCore.Qt.DisplayRole):
if orientation == QtCore.Qt.Horizontal and role == QtCore.Qt.DisplayRole:
return self.headers[section]
def flags(self,index):
if index.column()!=self.idIndex:
return QtCore.Qt.ItemIsEnabled | QtCore.Qt.ItemIsEditable | QtCore.Qt.ItemIsSelectable
else:
return QtCore.Qt.ItemIsSelectable
def setData(self, index,value,role=QtCore.Qt.EditRole):
if index.isValid():
sel_id=self.rows[index.row()][0]
sel_column=self.headers[index.column()]
if self.db.UpdateCell(self.tableName,sel_id,self.id,sel_column,value)==True:
self.rows[self.idFinder(self.rows,sel_id)][1]=value
self.dataChanged.emit(index,index)
return True
def insertRows(self):
print("inserting row!!!")
def removeRows(self):
pass
#find index of selected ID
def idFinder(self,data, search):
for i in range(len(data)):
for j in range(len(data[i])):
if data[i][j] == search:
return i
else:
return False
class EditTable(QtWidgets.QTableView):
def __init__(self):
super(EditTable, self).__init__()
self.setContextMenuPolicy(QtCore.Qt.CustomContextMenu)
self.customContextMenuRequested.connect(self.context_menu)
def context_menu(self):
context=QtWidgets.QMenu()
add_row=context.addAction("Add row")
add_row.triggered.connect(lambda: self.personnelTableModel.insertRows())
rem_row=context.addAction("Remove row")
rem_row.triggered.connect(lambda: self.personnelTableModel.removeRows())
cursor=QtGui.QCursor()
context.exec_(cursor.pos())
class MainWindow(QtWidgets.QMainWindow):
def __init__(self):
super(MainWindow, self).__init__()
widget = QtWidgets.QWidget()
layout = QtWidgets.QVBoxLayout()
widget.setLayout(layout)
button = QtWidgets.QPushButton("Push me")
self.db = maria_db.ConnectDb("localhost", "root", "1234", "test")
self.personnelTableModel = TableModel(self.db,"SELECT * FROM personnel","personnel","personnel_id")
table = EditTable()
table.setModel(self.personnelTableModel)
layout.addWidget(table)
layout.addWidget(button)
self.setCentralWidget(widget)
window = MainWindow()
window.show()
app.exec_()
所以我的问题是,当我调用add_row.triggered.connect(lambda: self.personnelTableModel.insertRows())
时,我得到了一个'EditTable' object has no attribute 'personnelTableModel'
,这实际上意味着self
中没有方法insertRows。如何通过子类本身引用分配给使用QTableView EditTable
子类构造的对象的模型?我会以错误的方式处理此问题吗?
EditTable的personalTableModel是什么?模型,以及如何从视图访问模型?使用model()方法。另一方面,不需要lambda方法。
def context_menu(self):
context=QtWidgets.QMenu()
add_row=context.addAction("Add row")
add_row.triggered.connect(self.model().insertRows)
rem_row=context.addAction("Remove row")
rem_row.triggered.connect(self.model().removeRows)
cursor=QtGui.QCursor()
context.exec_(cursor.pos())