Servlet中处理404错误

Question

我正在尝试根据状态代码重定向到其他错误jsp

statusCode = (Integer) req.getAttribute("javax.servlet.error.status_code") 但它抛出一个空指针错误。我的web.xml看起来像

<exception-type>404</exception-type><location>/AppExceptionHandler</location>

Answer 1

我认为web.xml中的条目不正确。它应该像下面这样。异常类型不应该是代码，而应该是下面的类。

异常类型包含完全限定的类Java异常类型的名称。

  <error-page>
    <exception-type>javax.servlet.ServletException</exception-type>
    <location>/AppExceptionHandler</location>
  </error-page>

如果您想处理404，请执行以下操作。

<error-page>
  <error-code>404</error-code>
  <location>/AppExceptionHandler</location>
</error-page>

Answer 2

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