Sun Jun 23 19:58:26 EDT 2024
There was an unexpected error (type=Internal Server Error, status=500).
could not extract ResultSet [ERROR: relation "users_seq" does not exist Position: 16] [select nextval('users_seq')]; SQL [select nextval('users_seq')]
org.springframework.dao.InvalidDataAccessResourceUsageException: could not extract ResultSet [ERROR: relation "users_seq" does not exist
Position: 16] [select nextval('users_seq')]; SQL [select nextval('users_seq')]
at org.springframework.orm.jpa.vendor.HibernateJpaDialect.convertHibernateAccessException(HibernateJpaDialect.java:277)
这是我从中传递数据的 thymeleaf 表单示例：
First Name: <input type="text" th:field="*{firstName}" />
<span th:if="${#fields.hasErrors('firstName')}"
th:errors="*{firstName}"
class="error"></span>
<br><br>
Username: <input type="text" th:field="*{userName}" />
<span th:if="${#fields.hasErrors('userName')}"
th:errors="*{userName}"
class="error"></span>
<br><br>
Email: <input type="text" th:field="*{email}" />
<span th:if="${#fields.hasErrors('email')}"
th:errors="*{email}"
class="error"></span>
<br><br>
这是使用表单数据的控制器方法：
@RequestMapping("/signup")
public String signup(Model theModel) {
User theUser = new User();
theModel.addAttribute("user", theUser);
return "signup";
}
@PostMapping("/confirmation")
public String confirmation(
@Valid @ModelAttribute("user") User theUser,
BindingResult bindingResult) {
if (bindingResult.hasErrors()) {
return "signup";
} else {
userService.save(theUser);
return "confirmation";
}
}
第一次使用Spring boot。肯定是傻眼了。不知道哪里需要更改模型。根据我的理解，使用 ModelAttribute 应该在提交表单时自动获取所有字段，对吗？
我的 Postgresql 数据库已创建，其中包含所有必要的列。也有联系。
这也是带有表设置的用户类：
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Integer id;
@NotNull(message="Name is required")
@Size(min=2, message="is required")
private String firstName;
@Size(message = "Username should be at least 5 characters")
@NotNull(message="Username is required")
private String userName;
@NotNull(message="Please enter a valid email address.")
@Email(message = "Not a valid email", regexp = "[a-z0-9._%+-]+@[a-z0-9.-]+\\.[a-z]{2,3}",
flags = Pattern.Flag.CASE_INSENSITIVE)
private String email;
@Min(16)
@NotNull(message = "Please enter an age above 16.")
private int age;
@Min(24)
@NotNull(message = "Please enter a height above 24 inches.")
private int height;
@NotNull(message = "You must select a gender for calorie assignment")
private String gender;
@NotNull(message = "Are you so lazy, you don't even wanna pick activity level?")
private String activityLevel;
@Min(85)
@NotNull(message = "You need to enter a weight above 85 pounds.")
private int weight;
@ManyToMany
@JoinTable(
name = "friends_list",
joinColumns = @JoinColumn(name = "user_id"),
inverseJoinColumns = @JoinColumn(name = "friend_id")
)
private Set<User> friendsList = new HashSet<>();
public String getGender() {
return gender;
}
public void setGender(String gender) {
this.gender = gender;
}
@Override
public boolean equals(Object o) {
if (this == o) {
return true;
}
if (!(o instanceof User)) {
return false;
}
User other = (User) o;
return id != null && id.equals(other.getId());
}
@Override
public int hashCode() {
return getClass().hashCode();
}
public User() {
}
public String getUserName() {
return userName;
}
public void setUserName(String userName) {
this.userName = userName;
}
public String getEmail() {
return email;
}
public void setEmail(String email) {
this.email = email;
}
public int getHeight() {
return height;
}
public void setHeight(int height) {
this.height = height;
}
public int getWeight() {
return weight;
}
public void setWeight(int weight) {
this.weight = weight;
}
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public void setActivityLevel(@NotNull(message = "Are you so lazy, you don't even wanna pick activity level?") String activityLevel) {
this.activityLevel = activityLevel;
}
public String getActivityLevel() {
return activityLevel;
}
public void setId(int id) {
this.id = id;
}
public int getId() {
return id;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
DDL：
create table users
(
id integer not null
primary key,
firstname varchar(255),
username varchar(255),
email varchar(255),
age integer,
height integer,
weight integer,
gender varchar(255),
activitylevel varchar(255)
);
alter table users
owner to #####;
将 @GenerateValue(strategy = GenerationType.AUTO) 更改为 @GenerateValue(strategy = GenerationType.IDENTITY) 并获取
2024-06-23T23:25:58.062-04:00 ERROR 5611 --- [fitBuddyApp] [nio-8080-exec-2] o.a.c.c.C.[.[.[/].[dispatcherServlet] : Servlet.service() for servlet [dispatcherServlet] in context with path [] threw exception [Request processing failed: org.springframework.dao.InvalidDataAccessResourceUsageException: could not execute statement [ERROR: column "activity_level" of relation "users" does not exist
Position: 20] [insert into users (activity_level,age,email,first_name,gender,height,user_name,weight) values (?,?,?,?,?,?,?,?)
好吧，我明白了。当我在终端上创建表时， 我没有将 id 添加为序列号。
所以我最终创建了一个序列，插入到表中，然后在用户代码中添加了这个花絮。
@Id
@GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "user_gen")
@SequenceGenerator(name = "user_gen",
sequenceName = "users_seq", allocationSize = 1)
private Integer id;
解决了问题。 Postgres 我想 seq 需要与表名匹配。