如何使用getGuestList获取名称，而不是电子邮件地址？

Question

我已经找到了这个脚本（由Jonathon发布），需要对其进行修改以提供用户名。

[当我尝试使用getGuestList()获取来宾名称时，它将在我的电子表格中返回EventGuest。

如何将访客姓名（而非电子邮件）输入电子表格？

function caltest3(){

var ss = SpreadsheetApp.openById( 'spreadsheetId' ),
  sheet = ss.getSheetByName( 'sheetName' ),
  cals = ['id1', 'id2', 'id3'], c, cal, calName,
  start = new Date( 'whenever' ), end = new Date( 'whenever' ),
  events, i, details,
  eventslog = [], e,
  rows = [], range;

for (c = 0; c < cals.length; c += 1) {

cal = CalendarApp.getCalendarById(cals[c]);
calName = cal.getTitle();
events = cal.getEvents(start, end);

// add the events of the current calendar to the array of all events
  eventslog = eventslog.concat(
   events.map(function(event) {
     return {
       time: new Date(event.getStartTime()).getTime(), // sort by this
        details: [
         event.getTitle(),
         event.getStartTime(),
         event.getEndTime(),
         event.getDescription(),
         event.getLocation(),
         calName // change calendar info position in array to suit
        ]
      };
    })
  );
 }

// sort array of event so date order can be either way by reversing a & b
eventslog.sort(function(a, b) { return a.time - b.time; });

rows = eventslog.map(function(entry) { return entry.details; });

range = sheet.getRange(2, 1, rows.length, 6);
range.setValues(rows);
}

Answer 1

您需要遍历Event.getGuestList()返回的来宾，并使用EventGuest.getName()，documented here检索每个名称。您应该验证名称是否为空，并且在这种情况下也许可以接受电子邮件-我会留给您。

这是您的功能将如何更改：

function caltest3(){

var ss = SpreadsheetApp.openById( 'spreadsheetId' ),
  sheet = ss.getSheetByName( 'sheetName' ),
  cals = ['id1', 'id2', 'id3'], c, cal, calName,
  start = new Date( 'whenever' ), end = new Date( 'whenever' ),
  events, i, details,
  eventslog = [], e,
  rows = [], range;

for (c = 0; c < cals.length; c += 1) {

cal = CalendarApp.getCalendarById(cals[c]);
calName = cal.getTitle();
events = cal.getEvents(start, end);

// add the events of the current calendar to the array of all events
  eventslog = eventslog.concat(
   events.map(function(event) {
     var deets =  {
       time: new Date(event.getStartTime()).getTime(), // sort by this
        details: [
         event.getTitle(),
         event.getStartTime(),
         event.getEndTime(),
         event.getDescription(),
         event.getLocation(),
         calName // change calendar info position in array to suit
        ]
      };
      var guestList = event.getGuestList();
      event.guests = [];
      for (var i in guestList) {
        event.guests.push(guestList[i].getName());
      } 
      deets.guests = guestList;
      return deets;
    })
  );
 }

Answer 2

我是这个菜鸟。谁能帮我？我有同样的问题，但无法解决。我想要给我的客人发送电子邮件或姓名。不，我只是获得EventGuest。没有数字或名称。

function getEvents（）{

var ss = SpreadsheetApp.getActiveSpreadsheet（）。getActiveSheet（）;var cal = CalendarApp.getCalendarById（“我的日历ID在这里正常”）;var events = cal.getEvents（new Date（“ 06/01/2020 12:00 AM”），new Date（“ 06/30/2030 12:00 AM”））;

var lr = ss.getLastRow（）;ss.getRange（2,1，lr-1,6）.clearContent（）;

for（var i = 0; i

var title = events[i].getTitle();
var sd = events[i].getStartTime();
var ed = events[i].getEndTime();
var loc = events[i].getLocation();
var des = events[i].getDescription();
var guest = events[i].getGuestList();


ss.getRange(i+2, 1).setValue(title);
ss.getRange(i+2, 2).setValue(sd);
ss.getRange(i+2, 2).setNumberFormat("dd/mm/yyyy /hh:mm");
ss.getRange(i+2, 3).setValue(ed);
ss.getRange(i+2, 3).setNumberFormat("dd/mm/yyyy /hh:mm");
ss.getRange(i+2, 4).setValue(loc);
ss.getRange(i+2, 5).setValue(des);
ss.getRange(i+2, 6).setValue(guest);

}}