Python Fabric任务可以调用其他任务并遵守其主机列表吗？

Question

我有一个如下所示的fabfile：

@hosts('host1')
def host1_deploy():
    """Some logic that is specific to deploying to host1"""

@hosts('host2')
def host2_deploy():
    """Some logic that is specific to deploying to host2"""

def deploy():
    """"Deploy to both hosts, each using its own logic"""
    host1_deploy()
    host2_deploy()

我想做

fab deploy

并且等同于

fab host1_deploy host2_deploy

换句话说，运行每个子任务，并为每个子任务使用其指定的主机列表。但是，这不起作用。相反，deploy（）任务需要自己的主机列表，并将其推广到其所有子任务。

这里有没有一种方法可以更新deploy（）任务，这样它就可以执行我想要的操作，而让子任务不受影响，因此它们可以单独运行？

Answer 1

从Fabric 1.3开始，execute帮助器现在可以执行此操作。该文档位于：Intelligently executing tasks with execute。

这是他们使用的示例：

from fabric.api import run, roles, execute

env.roledefs = {
    'db': ['db1', 'db2'],
    'web': ['web1', 'web2', 'web3'],
}

@roles('db')
def migrate():
    # Database stuff here.
    pass

@roles('web')
def update():
    # Code updates here.
   pass

然后从另一个任务migrate运行web和deploy：

def deploy():
    execute(migrate)
    execute(update)

并且这将尊重这些任务具有的角色和主机列表。

Answer 2

这很la脚，但从Fabric 1.1.2开始有效

def host1_deploy():
    """Some logic that is specific to deploying to host1"""
    if env.host in ["host1"]:
        pass #this is only on host2

def host2_deploy():
    """Some logic that is specific to deploying to host2"""
    if env.host in ["host2"]:
        pass #this is only on host2

def deploy():
    """"Deploy to both hosts, each using its own logic"""
    host1_deploy()
    host2_deploy()

这是我的测试代码：

@task
@roles(["prod_web","prod_workers"])
def test_multi():
    test_multi_a()
    test_multi_b()

def test_multi_a():
    if env.host in env.roledefs["prod_web"]:
        run('uname -a')

def test_multi_b():
    if env.host in env.roledefs["prod_workers"]:
        run('uname -a')

Answer 3

也许有更好的方法来处理它，但是您可以将两个主机都传递给deploy（），然后在host1_deploy（）和host2_deploy（）中检查env.host：

def host1_deploy():
    if env.host in ['host1']:
         run(whatever1)

def host2_deploy():
    if env.host in ['host2']:
         run(whatever2)

@hosts('host1','host2')
def deploy():
    host1_deploy()
    host2_deploy()

Answer 4

尝试这个。显然，您想用run或sudo替换local。关键是@hosts

的空deploy装饰器

from fabric.api import local
from fabric.decorators import hosts

@hosts('host1')
def host1_deploy():
    """Some logic that is specific to deploying to host1"""
    local('echo foo')

@hosts('host2')
def host2_deploy():
    """Some logic that is specific to deploying to host2"""
    local('echo bar')

@hosts('')
def deploy():
    """"Deploy to both hosts, each using its own logic"""
    host1_deploy()
    host2_deploy()