我正在使用以下 SQL 查询来更新临时表以便能够确定优先级。
这是我的SQL语句
UPDATE #CARD
SET rank_no = x.no_rank
FROM (
SELECT rank_no, chg_tot_amt, ROW_NUMBER() OVER (partition by pt_id ORDER BY [chg_tot_amt]) AS no_rank
FROM #CARD x where noproc =2
) x
where x.no_rank is not null
see the result below
pt_id rank_no chg_tot_amt no_rank
99999990 1 4722.3 1
99999990 1 17712.6 2
99999991 1 13643.26 1
99999991 1 15851.24 2
99999992 1 3814.94 1
99999992 1 18033.78 2
99999993 1 18033.78 1
99999993 1 19915.28 2
99999994 1 3814.94 1
99999994 1 15851.24 2
99999995 1 3814.94 1
99999995 1 15851.24 2
99999996 1 13643.26 1
99999996 1 15851.24 2
此语句将
rank_no
更新为 1,而不是预期的 1,2 或 3。
在此输入图片描述
您的子查询没有连接条件。
有加入条件:
UPDATE c
SET c.rank_no = x.no_rank
FROM #CARD c
INNER JOIN (
SELECT
pt_id, chg_tot_amt,
ROW_NUMBER() OVER (PARTITION BY pt_id ORDER BY chg_tot_amt) AS no_rank
FROM #CARD
WHERE noproc = 2
) x ON c.pt_id = r.pt_id AND c.chg_tot_amt = x.chg_tot_amt
WHERE x.no_rank IS NOT NULL
输出:
pt_id | 排名_编号 | chg_tot_amt |
---|---|---|
99999990 | 1 | 4722.30 |
99999990 | 2 | 17712.60 |
99999991 | 1 | 13643.26 |
99999991 | 2 | 15851.24 |
99999992 | 1 | 3814.94 |
99999992 | 2 | 18033.78 |
99999993 | 1 | 18033.78 |
99999993 | 2 | 19915.28 |
99999994 | 1 | 3814.94 |
99999994 | 2 | 15851.24 |
99999995 | 1 | 3814.94 |
99999995 | 2 | 15851.24 |
99999996 | 1 | 13643.26 |
99999996 | 2 | 15851.24 |