mov al,10
add al,15
如何打印 'al' 的值？
汇编语言没有直接打印任何内容的方法。您的汇编器可能会也可能不会提供提供此类功能的库，否则您必须自己编写它，这将是一个相当复杂的函数。您还必须决定在哪里打印内容 - 在窗口中还是在打印机上？在汇编程序中，这些都不是为你完成的。
DOS 打印存储在 EAX 中的 32 位值并以十六进制输出（适用于 80386+）
（在 64 位操作系统上使用 DOSBOX）
.code
mov ax,@DATA ; get the address of the data segment
mov ds,ax ; store the address in the data segment register
;-----------------------
mov eax,0FFFFFFFFh ; 32 bit value (0 - FFFFFFFF) for example
;-----------------------
; convert the value in EAX to hexadecimal ASCIIs
;-----------------------
mov di,OFFSET ASCII ; get the offset address
mov cl,8 ; number of ASCII
P1: rol eax,4 ; 1 Nibble (start with highest byte)
mov bl,al
and bl,0Fh ; only low-Nibble
add bl,30h ; convert to ASCII
cmp bl,39h ; above 9?
jna short P2
add bl,7 ; "A" to "F"
P2: mov [di],bl ; store ASCII in buffer
inc di ; increase target address
dec cl ; decrease loop counter
jnz P1 ; jump if cl is not equal 0 (zeroflag is not set)
;-----------------------
; Print string
;-----------------------
mov dx,OFFSET ASCII ; DOS 1+ WRITE STRING TO STANDARD OUTPUT
mov ah,9 ; DS:DX->'$'-terminated string
int 21h ; maybe redirected under DOS 2+ for output to file
; (using pipe character">") or output to printer
; terminate program...
.data
ASCII DB "00000000",0Dh,0Ah,"$" ; buffer for ASCII string
替代字符串直接输出到视频缓冲区，无需使用软件中断：
;-----------------------
; Print string
;-----------------------
mov ax,0B800h ; segment address of textmode video buffer
mov es,ax ; store address in extra segment register
mov si,OFFSET ASCII ; get the offset address of the string
; using a fixed target address for example (screen page 0)
; Position`on screen = (Line_number*80*2) + (Row_number*2)
mov di,(10*80*2)+(10*2)
mov cl,8 ; number of ASCII
cld ; clear direction flag
P3: lodsb ; get the ASCII from the address in DS:SI + increase si
stosb ; write ASCII directly to the screen using ES:DI + increase di
inc di ; step over attribut byte
dec cl ; decrease counter
jnz P3 ; repeat (print only 8 ASCII, not used bytes are: 0Dh,0Ah,"$")
; Hint: this directly output to the screen do not touch or move the cursor
; but feel free to modify..
PRINT_SUM PROC NEAR
CMP AL, 0
JNE PRINT_AX
PUSH AX
MOV AL, '0'
MOV AH, 0EH
INT 10H
POP AX
RET
PRINT_AX:
PUSHA
MOV AH, 0
CMP AX, 0
JE PN_DONE
MOV DL, 10
DIV DL
CALL PRINT_AX
MOV AL, AH
ADD AL, 30H
MOV AH, 0EH
INT 10H
PN_DONE:
POPA
RET
PRINT_SUM ENDP
调用 Win32 API 的 MessageBoxA 可能会有一些运气，尽管 Win16 是否支持该特定方法需要其他人来回答。
啊= 09 DS:DX = 指向以“$”结尾的字符串的指针
returns nothing
- outputs character string to STDOUT up to "$"
- backspace is treated as non-destructive
- if Ctrl-Break is detected, INT 23 is executed
参考：http://stanislavs.org/helppc/int_21-9.html
.data
string db 2 dup(' ')
.code
mov ax,@data
mov ds,ax
mov al,10
add al,15
mov si,offset string+1
mov bl,10
div bl
add ah,48
mov [si],ah
dec si
div bl
add ah,48
mov [si],ah
mov ah,9
mov dx,string
int 21h
假设您正在编写引导加载程序或其他可以访问 BIOS 的应用程序，以下是您可以执行的操作的粗略草图：
这是我的实现：
; Prints AL in hex.
printhexb:
push ax
shr al, 0x04
call print_nibble
pop ax
and al, 0x0F
call print_nibble
ret
print_nibble:
cmp al, 0x09
jg .letter
add al, 0x30
mov ah, 0x0E
int 0x10
ret
.letter:
add al, 0x37
mov ah, 0x0E
int 0x10
ret
; good example of unlimited num print
.model small
.stack 100h
.data
number word 6432
string db 10 dup('$')
.code
main proc
mov ax,@data
mov ds,ax
mov ax,number
mov bx ,10
mov cx,0
l1:
mov dx,0
div bx
add dx,48
push dx
inc cx
cmp ax,0
jne l1
mov bx ,offset string
l2:
pop dx
mov [bx],dx
inc bx
loop l2
mov ah,09
mov dx,offset string
int 21h
mov ax,4c00h
int 21h
main endp
end main
调用WinAPI函数（如果你正在开发win应用程序）
mov al,3 ;print ♥
mov dl,al
;call print service(2) to print from dl
mov ah,2
int 21h
;return to DOS
mov ah,76 ;76 = 4ch
int 21h ;call interrupt