如何跟踪用户尝试输入数据的总次数

Question

我做了一个非常简单的猜谜游戏。但我想计算用户在找到原始数字之前所做的尝试总和。这意味着一旦隐藏数字与用户输入匹配，它应该告诉用户在获胜之前输入了多少数字。

这是我的代码：

package guessinggame;

import java.util.Scanner;

public class GuessingGame {

    public static void main(String[] args) {

        int hiddenNum = 10;

        Scanner input = new Scanner(System.in);


        while (true) {
            System.out.println("Enter a numebr by guessing: ");

            int guessedNum = input.nextInt();


            if (guessedNum == hiddenNum) {
                System.out.println("Congratulation! Your number is matched");

                System.exit(0);

            } else if (guessedNum < hiddenNum) {
                System.out.println("Not matched! Try a bigger number");


            } else if (guessedNum > hiddenNum) {
                System.out.println("Not matched! Try a smaller number");

            }    
        } 
    }    
}

Answer 1

版本 } else if (猜测数 < hiddenNum) { System.out.println("Not matched! Try a bigger number");

                //checking another condition
            } else if (guessedNum > hiddenNum) {
                System.out.println("Not matched! Try a smaller number");

            }    
        } 
    }    
}

Answer 2

试试这个：

public static void main(String[] args) {
    //storing the hidden number in a variable
    int hiddenNum = 10;
    //introducing the scanner class (for user input)
    Scanner input = new Scanner(System.in);
    //asking user to enter a random number

    int attempts = 0; // use as a counter

    while (true) {
        System.out.println("Enter a numebr by guessing: ");
        //Storing that into a variable
        int guessedNum = input.nextInt();

        attempts += 1;

        //Checking wheather the number is matched
        if (guessedNum == hiddenNum) {
            System.out.println("Congratulation! Your number is matched");
            //System.out.println("You have made total of " + attempts +" attempts to find the number!");
            //If matched number found, terminate the program
            System.exit(0);
            //checking another condition
        } else if (guessedNum < hiddenNum) {
            System.out.println("Not matched! Try a bigger number");

            //checking another condition
        } else if (guessedNum > hiddenNum) {
            System.out.println("Not matched! Try a smaller number");

        }

    } 
}

Answer 3

此回复更适合在 http://codereview.stackexchange.com 但就在这里。

package guessinggame;

import java.util.Scanner;

public class GuessingGame {

    public static void main(String[] args) {

        int hiddenNum = 10;
        int guessedNum = 0;
        Scanner input = new Scanner(System.in);

        boolean running = true;

        for (int i = 1; running; i++) {
            System.out.println("Enter a number to guess: ");
            guessedNum = input.nextInt();

            if (guessedNum == hiddenNum) {
                System.out.println("Congratulation! Your number is matched");
                System.out.println("You have made " + i + " to find the number!");
                running = false;
            } else if (guessedNum < hiddenNum) {
                System.out.println("Not matched! Try a bigger number");
            } else {
                System.out.println("Not matched! Try a smaller number");
            }    
        } 
    }    
}

代码的一些更改：

• 您应该避免

  while (true)

  和“随机”终止程序。相反，我引入了

  boolean

  变量。它可以保存

  true

  或

  false

  的值。我一开始就把它设置为

  true

  ，然后如果用户猜对了，就把它设置为

  false

  。
• 我暂时删除了注释，通常当代码无法解释自己时应该使用注释。例如，这里是在 for 循环中使用它的一个很好的理由。 （在这里，

  while

  循环是更好的练习，我只是想展示一个

  for

  循环。）
• 对于最后一个条件检查，我删除了比较，无论是相等、更大还是更小。如果我们测试了相等和更大，那么剩下的都较小，因此只有

  else

  在那里。

Answer 4

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