呃,好吧,朋友们,现在我正在尝试为我的应用程序中的每个表格添加“导出到 Excel”功能,如下所示:
...
def update_exportable_tables(self, *window):
"""
Please don't ask why, here 'I know what I'm doing'
"""
if not window:
window = self.window
for obj in window.__dict__:
objname = obj.title().lower()
the_object_itself = window.__dict__[obj]
if isinstance(the_object_itself, (QTableWidget, QTableView)):
the_object_itself.setContextMenuPolicy(Qt.CustomContextMenu)
the_object_itself.customContextMenuRequested.connect(self.TableContextEvent)
def TableContextEvent(self, event):
menu = QMenu()
excelAction = menu.addAction(u"Export to Excel")
excelAction.triggered.connect(self.export)
action = menu.exec_(QCursor.pos())
def export(self):
print 'Here I should do export'
...
是的,它工作正常,但是....问题是我应该如何将单击的表实例传递给我的export()函数?
有几种不同的方法可以解决这个问题。这是一种方法:
def update_exportable_tables(self):
for widget in QtGui.qApp.allWidgets():
if isinstance(widget, QTableView):
widget.setContextMenuPolicy(Qt.CustomContextMenu)
widget.customContextMenuRequested.connect(self.showContextMenu)
def showContextMenu(self, pos):
table = self.sender()
pos = table.viewport().mapToGlobal(pos)
menu = QtGui.QMenu()
excelAction = menu.addAction("Export to Excel")
if menu.exec_(pos) is excelAction:
self.export(table)
def export(self, table):
print 'Here I should do export:', table
(注意:
QTableWidget
是 QTableView
的子类)。
好的,感谢 Eli Bendersky,我在谷歌上搜索了一种方法。
if isinstance(the_object_itself, (QTableWidget, QTableView)):
the_object_itself.setContextMenuPolicy(Qt.CustomContextMenu)
tricky = lambda: self.TableContextEvent(the_object_itself)
the_object_itself.customContextMenuRequested.connect(tricky)
...
def TableContextEvent(self, table_instance):
print table_instance
# ^^^^^^^^^^^^^ And yes, we have it!
upd1:它仍然是错误的,因为仅连接到一个实例(只有最后一个表实例在各处传递)