按Enter键需要提交下面角度4的表单是我的代码形式Action = ""
不工作。我还尝试使用(keydown) = domonething(event)
和(keydown.enter) = domonething(event)
以下代码
keyDownFunction(event) {
if (event.keyCode == 13) {
this.submit();
}
}
以下是我目前的代码
<form #f="ngForm" (ngSubmit)="f.form.valid && openModal(confirmationmodal)" novalidate action="">
<div class="form-group form-row">
<label class="col-form-label col-sm-4 col-md-4" for="name">Employee Name</label>
<div class="col-sm-8 col-md-8">
<span type="text" readonly class="form-control-plaintext" id="name">{{employeeDetails.EmployeeName}}</span>
</div>
</div>
<div class="form-group form-row">
<label class="col-form-label col-sm-4 col-md-4 " for="name">Manager Name</label>
<div class="col-md-8 col-sm-8">
<span type="text" readonly class="form-control-plaintext"
id="manager">{{employeeDetails.ManagerName}}</span>
</div>
</div>
<div class="form-group form-row">
<label for="name" class="col-sm-4 col-md-4 col-form-label">Subject</label>
<div class="col-md-8 col-sm-8">
<span type="text" readonly class="form-control-plaintext" id="manager">{{subject}}</span>
</div>
</div>
<button class="btn btn-success float-right" type="submit" id="submit">Submit</button>
</form>
在提交按钮中提供(keyup.enter)="yourFunction()"
这应该工作
(keydown)="keyDownFunction($event)
在打字稿中
keyDownFunction(event) {
if ( event.keyCode === 13) {
// do your function
}
}
这对我有用。我想你在比赛前错过了$。
如果你想用按钮调用它,你可以这样做 -
<button type="button" (keyup.enter)="doSomething()" >Click Me!</button>
看到这里 - https://stackblitz.com/edit/angular-3gf6hw
在这里查看更多相关信息 - https://angular.io/guide/user-input#key-event-filtering-with-keyenter
从您的表单标记我将删除action属性并将以下内容:
<form #f="ngForm" (ngSubmit)="f.form.valid && openModal(confirmationmodal)" novalidate (keydown.enter)="onEnterKeyDown($event)">
然后只需编写按键事件的功能:
onEnterKeyDown($event) {
// here you can open your confirmation modal if the form is valid
}
资料来源:https://alligator.io/angular/binding-keyup-keydown-events/