如何修复：随机抽奖号码程序的布尔数组。 “无法将int转换为boolean”

Question

我需要使用布尔数组为类创建一个随机的彩票生成器。起初我使用int数组并且它工作得很好但是当我将int数组更改为bool数组时，我得到一个错误，上面写着“类型不匹配：无法从int转换为boolean”。我想知道如何修复我的代码所以这将工作。

    int highestNumber, numsInLottery, randomNum;
    //int[] lottery = new int[numsInLottery];

    System.out.println("Welcome to the Lottery Number Generator!");
    System.out.println("How many numbers are in your lottery?");
    numsInLottery = TextIO.getInt();
    System.out.println("What is the highest number in your lottery?");
    highestNumber = TextIO.getInt();

    boolean[] lottery = new boolean[numsInLottery];

    for(int i = 0; i < numsInLottery; i++)
    {
        randomNum = (int)(Math.random() * highestNumber);
        for(int x = 0; x < i; x++ )
        {

            /*if (lottery[x] == randomNum)
            {
            randomNum = (int)(Math.random() * highestNumber);
            x = -1;
            }*/
        }   
        lottery[i] = randomNum;
        System.out.print(lottery[i] + " ");
    }

        //System.out.print(lottery[i] + " ");
    }
}

Answer 1

你正在为你的乐透[i]分配一个int

        lottery[i] = randomNum;

另一种方法是保留int数组，或者说

        lottery[i] = randomNum>(highestNumber/2);

所以你有一个布尔值而不是你的整数

Answer 2

假设您的布尔数组在随机索引处具有true和false值，您只需检查以下条件：

for(int x = 0; x < i; x++ ){

    if(lottery[x]){
        randomNum = (int)(Math.random() * highestNumber);
        x = -1;
    }
}