如何处理Selenium Python Google通讯录上的模态框

Question

我已经编写了一个代码，该代码应自动将联系人添加到Google通讯录。我处于最后阶段，但是由于弹出了一个模式框，所以一切都发生了变化。

    from selenium import webdriver
    from time import sleep
    fname="Misuzu"
    lname="Fusuzu"
    number=987654321

    driver=webdriver.Chrome()
    driver.get('https://contacts.google.com/')

    email=driver.find_element_by_id("identifierId")
    email.send_keys('[email protected]')
    psw='123456789'
    submit=driver.find_element_by_id("identifierNext")
    submit.click()
    sleep(2)
    password=driver.find_element_by_name("password")
    password.send_keys(psw)
    submit=driver.find_element_by_id("passwordNext")
    submit.click()
    sleep(2)

    create_contact=driver.find_element_by_xpath("//div[@class='aU2Vdf'][button/@class='VfPpkd-BIzmGd VfPpkd-BIzmGd-OWXEXe-X9G3K bgpk6e']")
    create_contact.click()
    sleep(10)
    #This is the part frome where my code stops working and raises the element not interactable error inspite of it being the part where I need to input my name. 
    driver.switch_to.active_element
    fnameins=driver.find_element_by_xpath("//div[@class='x3wWge'][//div[@class='Xb9hP'][input/@class='whsOnd zHQkBf']]")
    fnameins.click()
    lnameins=driver.find_element_by_xpath("//input[@class='whsOnd zHQkBf']")
    lnameins.send_keys(lname)
    numins=driver.find_element_by_xpath("//input[@class='whsOnd zHQkBf']")
    numins.send_keys(number)
    save=driver.find_element_by_xpath("//input[@class='VfPpkd-vQzf8d']")
    save.click()
    sleep(2)
    driver.quit()

Answer 1

"//div[@class='x3wWge'][//div[@class='Xb9hP'][input/@class='whsOnd zHQkBf']]"

• 是错误的xpath，它返回错误的Web元素

• 不要使用动态生成的@class属性的值，例如aU2Vdf（这些值很快就会改变）

• 我知道我没有回答，但是尝试搜索正确的xpaths

Answer 2

根据您的代码示例，我添加了几行与模式框进行交互，以帮助您入门。不过，您需要填补其余字段的空白。我已经测试了这段代码，并成功地将键发送到模式框元素。

driver=webdriver.Chrome()
driver.get('https://contacts.google.com/')

email=driver.find_element_by_id("identifierId")
email.send_keys('[email protected]')
psw='123456789'
submit=driver.find_element_by_id("identifierNext")
submit.click()
sleep(2)
password=driver.find_element_by_name("password")
password.send_keys(psw)
submit=driver.find_element_by_id("passwordNext")
submit.click()
sleep(2)

create_contact=driver.find_element_by_xpath("//div[@class='aU2Vdf'][button/@class='VfPpkd-BIzmGd VfPpkd-BIzmGd-OWXEXe-X9G3K bgpk6e']")
create_contact.click()

# wait for first name field to exist, then send text to it
first_name = WebDriverWait(driver, 10).until(
        EC.presence_of_element_located((By.XPATH, "//input[@aria-label='First name']")))

first_name.send_keys("test")

# enter more fields here

# click save
driver.find_element_by_xpath("//span[text()='Save']").click()

# if the above statement does not work, you can try the JS click:

#save_button = driver.find_element_by_xpath("//span[text()='Save']")
#driver.execute_script("arguments[0].click();", save_button)

# click cancel
driver.find_element_by_xpath("//span[text()='Cancel']").click()

# if the above statement does not work, you can try the JS click:

#save_button = driver.find_element_by_xpath("//span[text()='Cancel']")
#driver.execute_script("arguments[0].click();", save_button)

[在将文本发送到模式之前，请注意我如何调用WebDriverWait。我建议您也对脚本的其余部分也采用这种方法，而不是sleep(2)，您可以在等待存在的特定元素上调用WebDriverWait。这样，您将永远不会等待不必要的时间，并且如果页面加载所需的时间比正常时间长，脚本也不会失败。