在抛出'std :: invalid_argument'的实例之后调用terminate（）：stoi

Question

stoi函数崩溃程序与错误消息

"****@****:~> g++ -std=c++0x m1.cpp stimulation.h stims.h Task.h exoskeleton.h ARAIG_Sensors.h Profile.h

ARAIG_Sensors.h:1:9: warning: #pragma once in main file [enabled by default]

Profile.h:1:9: warning: #pragma once in main file [enabled by default]

*****@****:~> a.out StimulationConfig.csv TaskConfiguration.csv SampleProfileConfig.csv SampleOutput.txt

First : a.out
Second : StimulationConfig.csv
terminate called after throwing an instance of 'std::invalid_argument'
  what():  stoi
Aborted

我无法弄清楚为什么，有一个实例被传递到函数但仍然返回错误。也许有人可以帮我解决一下这个问题吗？

#pragma once
#include <string>
#include <vector>
#include "Task.h"
#include <ostream>
#include "ARAIG_Sensors.h"
namespace m1
{
    class Profile
    {
        ARAIG_Sensors araig;
        std::vector<Task> ToRun;
        std::vector<Task> Completed;
        std::string studentFN;
        std::string studentLN;
        std::string studentSN;
        std::string flightFN;
        std::string flightLN;
        std::string flightEN;
        std::ostream& os;

        struct calibration {
            int Max;
            int Min;
        };

        calibration cal;

    public:
        Profile(std::string fn, std::ostream& o, ARAIG_Sensors& a) : os(o)
        {
            araig = a;

            //parsing student
            std::ifstream infile(fn);
            std::string line;
            std::getline(infile, line);
            int f = line.find_first_of(",");
            studentFN = line.substr(0, f);
            line = line.substr(f + 1);
            f = line.find_first_of(",");
            studentLN = line.substr(0, f);
            studentSN = line.substr(f + 1);

            //parsing flight
            std::getline(infile, line);
            f = line.find_first_of(",");
            flightFN = line.substr(0, f);
            line = line.substr(f + 1);
            f = line.find_first_of(",");
            flightLN = line.substr(0, f);
            flightEN = line.substr(f + 1);

            //parsing calibration
            std::getline(infile, line);
            f = line.find_first_of(",");
            cal.Min = stoi(line.substr(0, f));
            std::cout << cal.Min << std::endl;
            line = line.substr(f + 1);
            cal.Max = stoi(line);



            std::list<Task> temp = araig.gettasks();
            while (std::getline(infile, line))
            {
                for (std::list<Task>::iterator i = temp.begin(); i != temp.end(); i++)
                {
                    if ((*i).getName() == line)
                    {
                        ToRun.push_back(*i);
                        break;
                    }



                }

            }

        }
        void displayToRun()
        {
            for (std::vector<Task>::iterator i = ToRun.begin(); i != ToRun.end(); i++)
            {
                (*i).execute(os);
            }
        }
        void displayCompleted()
        {
            for (std::vector<Task>::iterator i = Completed.begin(); i != Completed.end(); i++)
            {
                (*i).execute(os);
            }
        }
        void displayNext()
        {
            std::vector<Task>::iterator i = ToRun.begin();
            (*i).execute(os);
        }
        void displayLast()
        {
            std::vector<Task>::iterator i = Completed.end();
            (*i).execute(os);
        }
        void Run()
        {
            //excute next Task and move Task to Completed
            std::vector<Task>::iterator i = ToRun.begin();
            Task t = *i;
            t.execute(os);
            ToRun.erase(i);
            Completed.push_back(t);
        }
    };

}

Answer 1

这意味着你给std::stoi()输入错误，所以它抛出了你没有捕获的std::invalid_argument异常。

std::stoi, std::stol, std::stoll：

例外

• std::invalid_argument如果不能进行转换
• std::out_of_range如果转换后的值超出结果类型的范围，或者基础函数（std::strtol或std::strtoll）将errno设置为ERANGE。

std::terminate

当异常处理由于以下任何原因而失败时，C ++运行时调用std :: terminate（）：

1）抛出异常并且没有捕获（在这种情况下是否执行任何堆栈展开是实现定义的）

您需要仔细检查您尝试转换为整数的输入字符串值。它们不代表整数。