有人可以帮我吗？我无法找到一种简单的方法来检测球是否击中球拍，然后通过更改 rect_change_y 变量将其弹起。这是有效的代码，但当球击中游戏底部时，它不会与球拍交互或死亡。
import pygame
black = ( 0, 0, 0)
white = ( 255, 255, 255)
green = ( 0, 255, 0)
red = ( 255, 0, 0)
rect_x = 10
rect_y = 250
pad_x = 350
pad_y = 480
ball = 3
rect_change_x = 1
rect_change_y = 1
pad_x_c = 0
pygame.init()
size=[700,500]
screen=pygame.display.set_mode(size)
pygame.mouse.set_visible(0)
pygame.display.set_caption("Breakout Recreation WIP")
done=False
clock=pygame.time.Clock()
# -------- Main Program Loop -----------
while ball != 0:
# ALL EVENT PROCESSING SHOULD GO BELOW THIS COMMENT
for event in pygame.event.get(): # User did something
if event.type == pygame.QUIT: # If user clicked close
done=True # Flag that we are done so we exit this loop
keys = pygame.key.get_pressed() #checking pressed keys
if keys[pygame.K_LEFT]:
pad_x_c -= 2
elif keys[pygame.K_RIGHT]:
pad_x_c += 2
else :
pad_x_c = 0
# ALL EVENT PROCESSING SHOULD GO ABOVE THIS COMMENT
# ALL GAME LOGIC SHOULD GO BELOW THIS COMMENT
# ALL GAME LOGIC SHOULD GO ABOVE THIS COMMENT
# ALL CODE TO DRAW SHOULD GO BELOW THIS COMMENT
# First, clear the screen to white. Don't put other drawing commands
# above this, or they will be erased with this command.
screen.fill(black)
# Draw the rectangle
pygame.draw.rect(screen,white,[rect_x,rect_y,15,15])
pygame.draw.rect(screen,white,[pad_x,pad_y,50,10])
# Move the rectangle starting point
rect_x += rect_change_x
rect_y += rect_change_y
pad_x += pad_x_c
# Bounce the ball if needed
if rect_y > 480 or rect_y < 10:
rect_change_y = rect_change_y * -1
if rect_x > 680 or rect_x < 5:
rect_change_x = rect_change_x * -1
if pad_x <= 5 :
pad_x_c = 0
if pad_x >= 645 :
pad_x_c = 0
# ALL CODE TO DRAW SHOULD GO ABOVE THIS COMMENT
pygame.display.flip()
clock.tick(100)
pygame.quit ()
然后这里的代码应该可以工作（对我来说）但不能。
import pygame
black = ( 0, 0, 0)
white = ( 255, 255, 255)
green = ( 0, 255, 0)
red = ( 255, 0, 0)
rect_x = 10
rect_y = 250
pad_x = 350
pad_y = 480
ball = 3
rect_change_x = 1
rect_change_y = 1
pad_x_c = 0
pygame.init()
size=[700,500]
screen=pygame.display.set_mode(size)
pygame.mouse.set_visible(0)
pygame.display.set_caption("Breakout Recreation WIP")
done=False
clock=pygame.time.Clock()
# -------- Main Program Loop -----------
while ball != 0:
# ALL EVENT PROCESSING SHOULD GO BELOW THIS COMMENT
for event in pygame.event.get(): # User did something
if event.type == pygame.QUIT: # If user clicked close
done=True # Flag that we are done so we exit this loop
keys = pygame.key.get_pressed() #checking pressed keys
if keys[pygame.K_LEFT]:
pad_x_c -= 2
elif keys[pygame.K_RIGHT]:
pad_x_c += 2
else :
pad_x_c = 0
# ALL EVENT PROCESSING SHOULD GO ABOVE THIS COMMENT
# ALL GAME LOGIC SHOULD GO BELOW THIS COMMENT
# ALL GAME LOGIC SHOULD GO ABOVE THIS COMMENT
# ALL CODE TO DRAW SHOULD GO BELOW THIS COMMENT
# First, clear the screen to white. Don't put other drawing commands
# above this, or they will be erased with this command.
screen.fill(black)
# Draw the rectangle
pygame.draw.rect(screen,white,[rect_x,rect_y,15,15])
pygame.draw.rect(screen,white,[pad_x,pad_y,50,10])
# Move the rectangle starting point
rect_x += rect_change_x
rect_y += rect_change_y
pad_x += pad_x_c
# Bounce the ball if needed
if rect_y == pad_y:
if rect_x == pad_x:
rect_change_y = rect_change_y * -1
if rect_y > 490:
ball -= 1
rect_y = 250
rect_x = 10
rect_change_x = 1
rect_change_y = 1
if rect_y < 10:
rect_change_y = rect_change_y * -1
if rect_x > 680 or rect_x < 5:
rect_change_x = rect_change_x * -1
if pad_x <= 5 :
pad_x_c = 0
if pad_x >= 645 :
pad_x_c = 0
# ALL CODE TO DRAW SHOULD GO ABOVE THIS COMMENT
pygame.display.flip()
clock.tick(100)
pygame.quit ()
最后，关于如何制作方块并对它们做同样的事情，除了摧毁它们而不是球之外，有什么建议吗？
谢谢大家！
您可以使用
RectRect.move_ipmyrect = pygame.Rect(0, 0, 10, 10)
myrect.move_ip(100, 50)
myrect 左上角位于 (100, 50) 并保持相同的宽度和高度。
Rect.clamp_ipmyrect = pygame.Rect(100, 0, 10, 10)
bounds = pygame.Rect(0, 0, 50, 50)
myrect.clamp_ip(bounds)
myrect 左上角位于 (40, 0)，右下角位于 (10, 50)，位于 bounds 矩形内。
Rect.colliderectmyrect = pygame.Rect(0, 0, 10, 10)
another = pygame.Rect(5, 5, 10, 10)
print(myrect.colliderect(another)) # 1
由于 myrect 和 another 重叠，当你调用
colliderect我真的很喜欢 Pygame，所以我不介意应用这些建议重写你的程序。希望有帮助：
import pygame
# Constants
WIDTH = 700
HEIGHT = 500
SCREEN_AREA = pygame.Rect(0, 0, WIDTH, HEIGHT)
BLACK = (0, 0, 0)
WHITE = (255, 255, 255)
# Initialization
pygame.init()
screen = pygame.display.set_mode([WIDTH, HEIGHT])
pygame.mouse.set_visible(0)
pygame.display.set_caption("Breakout Recreation WIP")
clock = pygame.time.Clock()
# Variables
paddle = pygame.Rect(350, 480, 50, 10)
ball = pygame.Rect(10, 250, 15, 15)
paddle_movement_x = 0
ball_direction = (1, 1)
balls = 3
done = False
while not done and balls > 0:
# Process events
for event in pygame.event.get():
if event.type == pygame.QUIT:
done = True
keys = pygame.key.get_pressed()
if keys[pygame.K_LEFT]:
paddle_movement_x = -2
elif keys[pygame.K_RIGHT]:
paddle_movement_x = 2
else:
paddle_movement_x = 0
# Move paddle
paddle.move_ip(paddle_movement_x, 0)
paddle.clamp_ip(SCREEN_AREA)
# Move ball
ball.move_ip(*ball_direction)
if ball.right > WIDTH or ball.left < 0:
ball_direction = -ball_direction[0], ball_direction[1]
elif ball.top < 0 or ball.bottom > HEIGHT or paddle.colliderect(ball):
ball_direction = ball_direction[0], -ball_direction[1]
ball.clamp_ip(SCREEN_AREA)
# Redraw screen
screen.fill(BLACK)
pygame.draw.rect(screen, WHITE, paddle)
pygame.draw.rect(screen, WHITE, ball)
pygame.display.flip()
clock.tick(100)
pygame.quit()
每当我的球和球拍接近并接近击中对方时，但没有击中，它们就会互相传递。我该如何解决这个问题？