如何将2个不同数组中的数字组合成一个数组？

Question

我有一个代码，我生成随机数Colums = numCols和随机数Rows = numRows。 nomRows和numCols = numCells的倍数。我想用不同的颜色为每个Cell着色，我知道我拥有的Cell的总数，因为那是numCells。因此我有一个数组“颜色”，它有6个值。该数组中的每个数字代表该数组中该颜色的次数和次数。我有一个循环，为每种颜色生成一个随机数，但始终确保数组中的数字总数不会大于NumCells。你不能有23个颜色值，只有10个单元格适合它。现在这个工作正常，数组中的总数大小永远不会大于numCells。

所以我有一个数组颜色[]，其中包含6个数字，我想将该数组推入mysound2 []并在我推动之后创建一个nother循环，它将在该数组中再添加2个数字，最终得到一个数组mysound2 []其中包含8个数字的总数。

但我无法让它工作，要么我得到一个错误：无效类型'int [8] [int [6]]'对于数组下标我猜arduino不高兴到8的数组我只是试图添加6个号码。

或者如果我尝试其他的东西，代码会生成0,0,0。

请问如何将颜色[]推入mysoun2 []并再添加2个随机数？

// CODE FOR COLORS
``` int AnalogPin0 = A0; //Declare an integer variable, hooked up to analog pin 0
``` int AnalogPin1 = A1; //Declare an integer variable, hooked up to analog pin 1

void setup() {
  Serial.begin(9600); //Begin Serial Communication with a baud rate of 9600
  randomSeed(analogRead(0));

}

void loop() {
// 1)Gray, 2)White, 3)Yellow, 4)Blue, 5)Black, 6)Red

int numCols1  = random(1,4);
int numCols2  = random(2,5);
int numCols   = numCols1 + numCols2;

int numRows1  = random(2,5);
int numRows2  = random(2,6);
int numRows   = numRows1 + numRows2;

int numCells  = numCols * numRows;
int colors[]  = {5,3,2,1,0,0};
int numAlloc  = colors[0] + colors[1] + colors[2] + colors[3] + colors[4] + colors[5];


for (int i=0; i<numCells - numAlloc; i++)
{
  int color = random(0,7);
  color[colors]++;
}



  /*The Serial.print() function does not execute a "return" or a space
      Also, the "," character is essential for parsing the values,
      The comma is not necessary after the last variable.*/
Serial.print(colors [0]);     
Serial.print(",");
Serial.print(numCols);
Serial.print(",");
Serial.print(numRows);
Serial.print(",");
//Serial.print(numCells);
//Serial.print(",");
Serial.println();
delay(5000); // For illustration purposes only. This will slow down your program if not removed 
}


//CODE FOR ADDING 8 NUMBERS INTO ONE ARRAY WITH 2 LOOPS
# define Parameters 8
int mysound2[Parameters];
int randNumber =0;

void setup() {
   Serial.begin(9600);
     randomSeed(analogRead(0));
    for (int thisPin = 0; thisPin < Parameters-2; thisPin++)  {

    randNumber = random(1, 100); // generates between 0 and 127

    mysound2[thisPin]= randNumber;   

  }
    for (int thisPin = Parameters-2; thisPin < Parameters; thisPin++)  {

    randNumber = random(100, 200); // generates between 0 and 127

    mysound2[thisPin]= randNumber;   

  }
}

void loop() {
    for (int thisPin = 0; thisPin < Parameters; thisPin++)  {
     Serial.println(mysound2[thisPin]);  
     delay(5000);
}
}


//ME TRYING TO COMBINE THE TWO CODES
// 1)Gray, 2)White, 3)Yellow, 4)Blue, 5)Black, 6)Red

# define Parameters 8

int numCols1  = random(1,4);
int numCols2  = random(2,5);
int numCols   = numCols1 + numCols2;

int numRows1  = random(2,5);
int numRows2  = random(2,6);
int numRows   = numRows1 + numRows2;

int numCells  = numCols * numRows;
int colors[]  = {5,3,2,1,0,0};
int numAlloc  = colors[0] + colors[1] + colors[2] + colors[3] + colors[4] + colors[5];
int color     = 0;

int mysound1[Parameters];
int randNumber1 =0;

void setup() {
   Serial.begin(9600);
     randomSeed(analogRead(0));
    for (int thisPin = 0; thisPin < Parameters-2; thisPin++)  
    {
      for (int i=0; i<numCells - numAlloc; i++)
      {
        int color = random(0,6);
        color[colors]++;
        }
       mysound1[color];
      }

  for (int thisPin = Parameters-2; thisPin < Parameters; thisPin++)  {

    randNumber1 = random(100, 200); // generates between 0 and 127

    mysound1[thisPin]= randNumber1;   
  }
}

void loop() {
    for (int thisPin = 0; thisPin < Parameters; thisPin++)  {
     Serial.println(mysound1[color]);  
     delay(2000);
    }
}

Answer 1

我知道你想将一个数组复制到另一个数组中。你可以用这样的函数做到这一点：

void copyArray(int* source, int* destination, int length) {
    for (int i = 0; i < length; i++) {
        *destination++ = *source++;
    }
}

因此，如果你想将qazxsw poi中的6个元素复制到qazxsw poi中，qazxsw poi会这样做。

如果你想再添加2个元素，可以这样做。

colors

编辑：在评论部分，您提到要将两个数组合并为一个。像这样的函数会这样做。

mysound2

下面的代码将copyArray(colors, mysound2, 6);复制到

mysound2[6] = randNumber1;
mysound2[7] = randNumber2;

的前6个字节，并将

void copyArray(int* source, int* destination, int destStartIndex, int len) {
  for (int i = 0; i < len; i++) {
        destination[destStartIndex + i] = *source++;
    }
}

复制到colors的以下2个字节。

mysound2