如何在Lua中执行异步功能?

问题描述 投票:0回答:1

我在一个函数中有一个数据库查询,该函数返回该查询的结果,而在另一个函数中,我想检索该结果,但我不知道如何异步执行。我正在对数据库查询使用“ mysqloo”库https://github.com/FredyH/MySQLOO

第一个函数,带有查询:

function meta:getMoney()
    local query2 = databaseObject:query("SELECT economy FROM luvinsastroi_player WHERE steamid = '" .. self:SteamID64() .. "' ")

    query2.onData = function( q, d)
        return tonumber(d['economy'])
    end
    query2:start()
end

然后:

hook.Add( "PlayerSay", "MoneyCommand", function( ply, text, team )
    if(text == "/money") then
        local money = ply:getMoney()
        ply:PrintMessage( HUD_PRINTTALK, "Vous avez " .. money .. "€." )
    end
end )

在第二个函数中,金钱为零,因此Error on ply:PrintMessage ( HUD_PRINTTALK, "Vous avez " .. money .. "€." ) attempt to concatenate a nil value (money)

如何从return tonumber(d['economy'])功能等待meta:getMoney()

asynchronous lua garrys-mod
1个回答
0
投票

这可能有用,但是我不确定:

function meta:getMoney(cb)
   local query2 = databaseObject:query("SELECT economy FROM luvinsastroi_player WHERE steamid = '" .. self:SteamID64() .. "' ")
   if cb then 
      query2.onData = function(q, d)
         cb(tonumber(d['economy']))
      end
   else
      query2.onData = function(q, d)
         return tonumber(d['economy'])
      end
   end
   query2:start()
end


hook.Add("PlayerSay", "MoneyCommand", function(ply, text, team)
   if(text == "/money") then
      local function callback_money(money)
         ply:PrintMessage(HUD_PRINTTALK, "Vous avez " .. money .. "€." )
      end
      ply:getMoney(callback_money)
   end
end)
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