CS50 用餐问题，Python 3，convert() 函数返回小数值时出错

Question

所以我们应该提示用户输入时间为#:## a.m./p.m.，函数convert应该将输入的时间转换为浮点数，返回浮点数并使用打印足够的文本。

我收到一条错误，指出转换函数未返回十进制值，但当我手动输入时，终端正在通过所有测试。

出了什么问题？

def main():

    text = input("time here: ")
    time = convert(text) # call the function convert() and assign it to time variable, different from the one in the function
    print(time, type(time)) # check if the function returns a float value

    if 7 <= time <= 8: # simple logic for defining time
        print("breakfast time")
    elif 12 <= time <= 13:
        print("lunch time")
    elif 18 <= time <= 19:
        print("dinner time")
    elif time >= 24: # ensure that you can't type in number > 24
        print("Not a valid time point.")
    else:
        None # print None (null) for other cases

def convert(time):

    hour, minute, period = time.replace(":", " ").split(" ") # unpack the list with 3 arguments (3rd arugment is period = am/pm) and define floats
    hour = float(hour)
    minute = float(minute) / 60
    n_time = hour + minute # assign to a new variable n_time which should return float

    return round(n_time, 2) # return float, rounded to 2 decimals


if __name__ == "__main__":
    main()

Answer 1

根据规格：

假设用户的输入将以 24 小时时间格式格式化为 #:## 或 ##:##

此行将因该输入而出错：

hour, minute, period = time.replace(":", " ").split(" ") # unpack the list with 3 arguments (3rd arugment is period = am/pm) and define floats

错误

挑战说[强调]：

如果愿意接受挑战，可以选择添加对 12 小时时间的支持，允许用户以这些格式输入时间 too:

#:## 上午和 ##:## 上午
#:## 下午下午 ##:##

挑战必须处理任一格式。