如何使用Scrapy + Splash在同一页面上单击2个按钮?

问题描述 投票:0回答:1

单击链接弹出通知后会出现一个页面。因此,要按照链接lua脚本应单击按钮1,然后单击按钮2(在弹出通知上接受),然后继续下一页。我的脚本没有点击按钮2.我错在哪里?

class PalmBeachSpider(scrapy.Spider):

    name ='splash'
    custom_settings = {
        'SPLASH_URL' : 'http://localhost:8050',
        'DOWNLOADER_MIDDLEWARES' : {
                                    'scrapy_splash.SplashCookiesMiddleware': 723,
                                    'scrapy_splash.SplashMiddleware': 725,
                                    'scrapy.downloadermiddlewares.httpcompression.HttpCompressionMiddleware': 810,
                                },
        'SPIDER_MIDDLEWARES' : {
                                'scrapy_splash.SplashDeduplicateArgsMiddleware': 100,
                                             }
    }






    script = '''
                function main(splash, args)
                assert(splash:go(args.url))
                assert(splash:wait(0.5))
                assert(splash:runjs('document.querySelector("#bodySection > div > div > div:nth-child(7) > div > div:nth-child(2) > a").click()'))
                assert(splash:wait(3.5))
                assert(splash:runjs('document.querySelector("a#idAcceptYes").click()'))
                return {
                html = splash:html(),


                  }
                end'''
    def start_requests(self):
        url  = 'https://apps.stjohnsclerk.com/Landmark'
        yield SplashRequest(url = url, callback = self.parse, endpoint = 'execute', args={'wait': 0.5, 'lua_source' : self.script})

    def parse(self, response):
        inspect_response(response, self)
        response = HtmlResponse(url=response.url, body=response.data['html'], encoding = 'utf-8')
python-3.x scrapy splash scrapy-splash
1个回答
1
投票

你可以在最后一次启动后添加另一个'assert(splash:wait(...)):runjs。

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