我不再在pycharm中的python代码上获取输出文件

Question

不再在pycharm上获取输出文件。

我以前有一个输出文件，但是不会随着“ data_to_write”中的更改而更新。我将输出文件移到了另一个位置，但没有更改我需要生成的输出文件的输出目录路径。 Pycharm不再创建输出文件。

def main():
driver = gdal.GetDriverByName('JPEG')
driver.Register()

sdsu_in = './data/SDSU_3Color.jpg'
# open and read only jpeg file
data = gdal.Open(sdsu_in, gdalconst.GA_ReadOnly)

if data is None:
    print("Error: Could not read '{}'".format(sdsu_in))
    sys.exit()

rows = data.RasterYSize
cols = data.RasterXSize
r_bands = data.RasterCount
proj = data.GetProjectionRef()
m_data = data.GetMetadata()
geotrans = data.GetGeoTransform()
x_origin = geotrans[0]
y_origin = geotrans[3]
pixel_width = geotrans[1]
pixel_height = geotrans[5]

print("The # of rows: {}, The # of columns: {}, raster bands: {}, "
      "metadata: {}".format(rows, cols, r_bands, proj, m_data))

data_to_write = f'The number of rows: {rows}\n The number of columns 
{cols}\n The number of raster bands: {r_bands}\n The projection: {proj}\n 
The metadata: {m_data}\n The Geotransform information: {geotrans}\n X 
Origin: {x_origin}\n Y Origin: {y_origin}\n Pixel Width: {pixel_width}\n 
Pixel Height: {pixel_height}'

# creating new output with specified information
sdsu_out = './output/output_w1.txt'
with open(sdsu_out, 'w') as f:
    f.write(data_to_write)
    f.flush()
    f.close()

if __name__ == '__main__':
    main()

代码比这更长，但这是我需要创建的简单.txt文件。昨晚我得到了一个输出，但是它不会随着更改的代码而更新，因此我添加了一个“ 1”以结束（希望）在输出目录中创建一个新文件。我没有更改输出目录的相对路径。其余代码很长，因此我没有上载它。调试时没有红色错误，只有6个弱警告。

谢谢您的帮助。**代码在pycharm上完美缩进，但不会在每行中添加4个空格。.

Answer 1

我认为，某些事情改变了您Pycharm环境的当前工作目录。

只需在with open(语句之前添加以下行。它将打印出当前的工作目录。然后，我建议您使用文件浏览器并查看该目录，以查看是否确实没有创建文件]

print("I will create the file ", sdsu_out, "in the directory ", os.path.realpath(os.path.getcwd())

并添加行

import os

如果尚未导入os，则在文件的开头。

Answer 2

from osgeo import gdal, gdalconst
import sys
import random
import os
import numpy as np

def main():


    driver = gdal.GetDriverByName('JPEG')
    driver.Register()

    sdsu_in = './data/SDSU_3Color.jpg'
    data = gdal.Open(sdsu_in, gdalconst.GA_ReadOnly)

    if data is None:
        print("Error: Could not read '{}'".format(sdsu_in))
        sys.exit()

    rows = data.RasterYSize
    cols = data.RasterXSize
    r_bands = data.RasterCount
    proj = data.GetProjectionRef()
    m_data = data.GetMetadata()
    geotrans = data.GetGeoTransform()
    x_origin = geotrans[0]
    y_origin = geotrans[3]
    pixel_width = geotrans[1]
    pixel_height = geotrans[5]

    print("The # of rows: {}, The # of columns: {}, raster bands: {}, "
      "metadata: {}".format(rows, cols, r_bands, proj, m_data))

    data_to_write = f'The number of rows: {rows}\n The number of ' \
    f'columns: {cols}\n The number of raster bands: {r_bands}\n The ' \
    f'projection: {proj} The metadata: {m_data}\n The Geotransform  ' \ 
    f'information: {geotrans}\n X Origin: {x_origin}\n Y Origin: ' \ 
    f'{y_origin}\n Pixel Width: {pixel_width} Pixel Height: ' \ 
    f'{pixel_height}'

    # creating new output with specified information
    # relative path
    sdsu_out = './output/output_wozniak.txt'
    # tried absolute path to get output but not luck :(
    sdsu_out1 = 'C:/Users/sarah/PycharmProjects/GEOG582/a08_wozniak/output/output_wozniak1.txt'

    print("I will create the file ", sdsu_out, "in the directory ", os.path.realpath(os.path._getfullpathname()))
    with open(sdsu_out, 'w') as f:
        f.write(data_to_write)
    # f.flush()
    # f.close()


    if __name__ == '__main__':
    main()