从 ViewController 调用时如何检索存储在单独类中的数据?

问题描述 投票:0回答:4

我目前正在学习使用 Swift 进行 iOS 开发。我正在制作一个简单的天气应用程序。我有几个按钮可以获取未来 4 小时的天气情况。我从 dark sky API 获取天气,以 JSON 格式返回。我终于弄清楚如何从 JSON 中检索正确的数据,并创建了一个用于获取数据的类。

typealias WeatherCallback = (Weather) -> Void
typealias ErrorCallback = (Error) -> Void

class NetworkManager {
    
    class func getWeather(latitude: String, longitude: String, onSuccess: WeatherCallback? = nil, onError: ErrorCallback? = nil) {
        
        let urlString = "https://api.darksky.net/forecast/(api key)/" + latitude + "," + longitude + "?units=si"
        
        let url = URL(string: urlString)
        
        URLSession.shared.dataTask(with: url!) { (data, response, error) in
            if error != nil {
                print(error!)
                onError?(error!)
            } else {
                do {
                    let json  = JSON(data: data!)
                    let weather = Weather()
                    
                    DispatchQueue.main.async {
                        weather.updateWithJSON(dict: json["currently"], hour: 0)
                        
                        for i in 1...4 {
                            weather.updateWithJSON(dict: json["hourly"]["data"][i], hour: i)
                        }
                    }
                    onSuccess?(weather) 
                }
            }
            }.resume()
    }
}

我有一个不同的类来存储检索到的数据。

class Weather {
   
    public var currentTime: String = ""
    public var currentTemperature: String = ""
    
    public var nextHourTime: String = ""
    public var nextHourTemperature: String = ""
    
    public var nextTwoHourTime: String = ""
    public var nextTwoHourTemperature: String = ""
    
    public var nextThreeHourTime: String = ""
    public var nextThreeHourTemperature: String = ""
    
    public var nextFourHourTime: String = ""
    public var nextFourHourTemperature: String = ""
    
    func updateCurrentData(time: String, temp: String) {
        currentTime = time
        currentTemperature = temp
    }
    
    func updateWithJSON(dict: JSON, hour: Int){
        
        switch hour {
        case 0:
            currentTime = dict["time"].stringValue
            currentTemperature = dict["temperature"].stringValue
            
        case 1:
            nextHourTime = dict["time"].stringValue
            nextHourTemperature = dict["temperature"].stringValue
            
        case 2:
            nextTwoHourTime = dict["time"].stringValue
            nextTwoHourTemperature = dict["temperature"].stringValue
            
        case 3:
            nextThreeHourTime = dict["time"].stringValue
            nextThreeHourTemperature = dict["temperature"].stringValue
            
        case 4:
            nextFourHourTime = dict["time"].stringValue
            nextFourHourTemperature = dict["temperature"].stringValue
            
        default:
            print("rip")
        }
    }
}

我的问题是,我无法从

Weather
中访问类
ViewController
中存储的值。

例如

让天气 = Weather()

打印(天气.当前时间)

任何帮助我指明正确方向的帮助都会很棒!

ios json swift
4个回答
1
投票

您可以通过创建

Weather
Singleton
来做到这一点。使用单例 该对象仅存在一个副本,并且状态可由任何其他对象共享和访问。

class Weather {
public static var sharedInstance =  Weather()
...
private init() {
}
}

并像这样获取单例对象

let weather = Weather.sharedInstance // it will give you the same instance of Weather every time you call it.

1
投票

您可以使用委托模式在视图控制器中获取结果。首先创建一个这样的协议:

protocol YourDelegateProtocol {
    func getDataFromServer(data: String)
}

之后,在 NetworkManager 类中创建此协议的实例,如下所示:

class NetworkManager {
    var delegate: YourDelegateProtocol?    
}

收到响应后,将响应从那里发送到您的视图控制器:

URLSession.shared.dataTask(with: url!) { (data, response, error) in
        if error != nil {
            print(error!)
            onError?(error!)
        } else {
            do {
                let json  = JSON(data: data!)
                  delegate.geDataFromServer(json as String)
                }
                onSuccess?(weather) 
            }
        }
        }.resume()

之后像这样获取视图控制器中的数据

class WeatherData: UIViewController, YourDelegateProtocol {

   var yourModelClass = YourModelClass() //init model class globally.

   func getDataFromServer(data: String) {
    // populate json String into your model class. Then you are ready to go.
   }
}

0
投票

您可以在 ViewController 中创建请求 getWeather。此函数使您可以访问作为完成处理程序的 Weather 对象(WeatherCallback = (Weather) -> Void)。


0
投票

这里可以使用单例设计模式。创建一个 Singleton

Weather
类,每当您收到
getWeather
函数的响应时,都会更新您的
Weather
单例类。当您想要用户响应时,只需从
Weather
类获取值即可。

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