我正在尝试在子查询中计算以一对多关系连接的列的总和，并按外键分组，以便对于与同一键相关的每个记录，都有所有这些记录的小计.
我尝试的子查询是
(SELECT SUM(est_valuation.total_value)
FROM est_valuation
WHERE est_valuation.current_val = 'Y'
GROUP BY est_valuation.site_id)
AS 'Combined Valuation(s) Total'
它可以在没有
GROUP BY我尝试完成此操作但出现错误
SQLSTATE[21000]：基数违规：1242 子查询返回更多 超过 1 行
我已经没有主意了
e:
这是整个查询
SELECT
site.site_code AS 'Site Code',
site.site_desc AS 'Site Description',
site.site_alias AS 'Site Alias',
site_type.site_type_desc AS 'Site Description',
site_designation.site_designation_desc AS 'Site Designation',
site_classification.site_classification_desc AS 'Site Classification',
site.uprn AS 'UPRN',
site.addr_first_obj AS 'Address First Line',
site.addr_second_obj AS 'Address Second Line',
site.addr_street AS 'Address Street',
site.addr_locality AS 'Address Locality',
site.addr_town AS 'Address Town',
site.addr_region AS 'Address Region',
site.addr_postcode AS 'Address Postcode',
ward.ward_desc AS 'Ward',
parish.parish_desc AS 'Parish',
district.district_desc AS 'District',
prop_facility_asset_category_type.prop_facility_asset_category_type_desc AS 'IFRS Type',
prop_facility_asset_category.prop_facility_asset_category_desc AS 'IFRS Category',
site_usage.site_usage_desc AS 'Site Usage',
committee.committee_desc AS 'Committee',
site.area AS 'Area',
SUM(building.gia) AS 'GIA',
CONCAT(building_age.building_age_desc) AS 'Building Age',
site.vacant AS 'Vacant',
site.vacant_date AS 'Vacancy Date',
site.comment AS 'Comment',
gen_userdef_group.user_text1,
gen_userdef_group.user_text2,
gen_userdef_group.user_text3',
gen_userdef_group.user_text4,
gen_userdef_group.user_text5,
gen_userdef_group.user_text6,
gen_userdef_group.user_check1,
gen_userdef_group.user_check2,
gen_userdef_group.user_check3,
gen_userdef_group.user_check4,
prop_strategy.strategy_strap_line,
prop_strategy.current_strategy AS,
prop_strategy.strategy_maintenance,
prop_strategy.comments,
prop_strategy.last_review_date,
(SELECT SUM(est_valuation.total_value)
FROM est_valuation
WHERE est_valuation.current_val = 'Y'
GROUP BY est_valuation.site_id)
AS 'Combined Valuation(s) Total
FROM site
LEFT JOIN site_type
ON site.site_type_id = site_type.site_type_id
LEFT JOIN site_designation
ON site.site_designation_id = site_designation.site_designation_id
LEFT JOIN site_classification
ON site.site_classification_id = site_classification.site_classification_id
LEFT JOIN ward
ON site.ward_id = ward.ward_id
LEFT JOIN parish
ON site.parish_id = parish.parish_id
LEFT JOIN district
ON site.district_id = district.district_id
LEFT JOIN prop_facility_asset_category
ON site.prop_facility_asset_category_id = prop_facility_asset_category.prop_facility_asset_category_id
LEFT JOIN site_usage
ON site.site_usage_id = site_usage.site_usage_id
LEFT JOIN committee
ON site.committee_id = committee.committee_id
LEFT JOIN building
ON site.site_id = building.site_id
LEFT JOIN building_age
ON building.building_age_id = building_age.building_age_id
LEFT JOIN gen_userdef_group
ON site.gen_userdef_group_id = gen_userdef_group.gen_userdef_group_id
LEFT JOIN prop_facility_asset_category_type
ON prop_facility_asset_category.prop_facility_asset_category_type_id = prop_facility_asset_category_type.prop_facility_asset_category_type_id
LEFT JOIN prop_facility_asset_subcategory
ON prop_facility_asset_category.prop_facility_asset_subcategory_id = prop_facility_asset_subcategory.prop_facility_asset_subcategory_id
LEFT JOIN prop_strategy
ON site.site_id = prop_strategy.site_id
LEFT JOIN est_valuation
ON site.site_id = est_valuation.site_id
WHERE site.active = 'Y'
GROUP BY site.site_code;````
04/07/2024 update:
I've picked this one back up again, I've tried making it a correlated subquery as advised
adding
````SELECT total_value
and
WHERE site.active = 'Y'
AND total_value =
(SELECT SUM(est_valuation.total_value)
FROM est_valuation
WHERE est_valuation.current_val = 'Y') ````
which makes the query valid again but also returns zero rows
您的子查询应包含现场过滤器，以确保它返回 1 行。删除分组依据并尝试
WHERE est_valuation.current_val = 'Y' AND est_valuation.site_id=site.site_code