获取用户关注的不同用户的所有对象属性的列表 - symfony

Question

我正在构建一个书籍应用程序，供用户查看您上传的书籍，他/她必须关注您或成为您的朋友。该应用程序由3个实体书籍，用户和关注组成。这是一个示例结构Follow表

id | followered_id | followed_id
1  | 1             | 2
2  | 1             | 3
3  | 2             | 1

从上面的illutration用户1跟随/朋友到2和3.所以他们所有的书应该出现在他的个人资料中。在下面的控制器中，我能够尝试，但我必须点击每个用户才能查看他上传的书籍

$em = $this->getDoctrine()->getManager();

        $me = $this->getAuthedUser(1);

        $follows = $em->getRepository("AppBundle:Follow")->findBy(["follower" => $me]);
        $followeds = [];
        foreach ($follows as $follow) {
            $followeds[] = $follow->getFollowed();
        }

        $followables = $em->getRepository("AppBundle:User")->findAll();



        return $this->render("@App/index.html.twig", [
            "me" => $me,
            "followeds" => $followeds, //this
            "followables" => $followables,
        ]);

以下是上述控制器方法的视图

<h1>Welcome, {{ me.username }}!</h1>

        <h2>Your followed people:</h2>
        {% if followeds is not empty %}
            <ul>
            {% for followed in followeds %}
                <li>{{ followed.username }} (<a href="{{ path('profile', {user: followed.id}) }}">see his profile</a>)</li>
            {% endfor %}
            </ul>
        {% else %}
            you don't follow anyone yet.
        {% endif %}

这是以下声明的实体片段

/**
     * @var User
     *
     * @ORM\ManyToOne(targetEntity="AppBundle\Entity\User")
     */, Kindly help me to get out of this. 

并告诉我是否需要任何进一步的信息。先感谢您。私人追随者;

    /**
     * @var User
     *
     * @ORM\ManyToOne(targetEntity="AppBundle\Entity\User")
     */
    private $followed;

我目前面临的挑战是能够看到用户发布的书籍的所有属性，例如我所关注的书名，出版商等，而不点击上传它的用户。

Answer 1

{% for followed in followeds %}
                <li> <!-- your followed profile link etc.--> </li>
    {% if followed.books %}
    <ul>
        {% for book in followed.books %}
            <li>{{ book.title }}</li>
        {% endfor %}
    <ul>
    {% endif %}
{% endfor %}