elem1.Location as LocationPoint).Point 在下面的代码中返回 null。谁能帮我解决这个问题吗？

Question

该代码似乎旨在选择多个文本元素，然后以特定的水平距离排列它们。

IList<Reference> selectedRefs = uiDoc.Selection.PickObjects(ObjectType.Element,"Select text instances");

    if (selectedRefs.Count < 2)
    {
                    TaskDialog.Show("Error", "Select at least two text instances.");
                    return Result.Cancelled;
    }

                // Calculate the desired equal horizontal distance between text instances
    double desiredHorizontalDistance = 50.0; // Change this value as needed

    using (Transaction tx = new Transaction(doc, "Move Text "))
    {
      tx.Start();

                    // Sort selected text instances by their X-coordinates
      List<Element> selectedTextInstances = new List<Element>();
      foreach (Reference reference in selectedRefs)
      {
       Element textElement = doc.GetElement(reference);
       selectedTextInstances.Add(textElement);
      }

      selectedTextInstances.Sort((elem1, elem2) =>
      {
       XYZ point1 = (elem1.Location as LocationPoint).Point;
       //XYZ point1 = elem1.Coord;
       XYZ point2 = (elem2.Location as LocationPoint).Point;
       return point1.X.CompareTo(point2.X);
       });}

Answer 1

文本元素的

Location

属性可以由多个点组成，具体取决于文本对齐设置。因此，属性值不能用

LocationPoint

或

LocationCurve

来表示。因此，不幸的是，Revit API 不提供任何读取或写入此属性的可能性。