如何显示在Vue.js中创建/加载的组件/页面上的模式

Question

我是Vue.js的新手，我在模式上苦苦挣扎。我想在用户导航到某个组件时首先加载模式窗口。我尝试创建一些示例模态，如果单击按钮并触发$('#modalId').modal('show')，它将打开。但是，当我尝试从Vue的created () {...}执行相同的命令时，它不会打开模式窗口。我不想单击按钮来打开模式窗口，我想在页面/组件加载时打开。

    <!-- This works fine -->
    <button class="btn btn-dark" @click="openModal" data-target="#loginModal">Open modal</button>

    <!-- MODAL -->
    <div class="modal" ref="modal" id="loginModal" data-keyboard="false" data-backdrop="static">
      <div class="modal-dialog">
        <div class="modal-content">
          <div class="modal-header">
            <h5 class="modal-title">Insert required data</h5>
          </div>
          <div class="modal-body">
            <form>
              <div class="form-group">
                <label for="username">Username</label>
                <input type="text" class="form-control">
              </div>
            </form>
          </div>
          <div class="modal-footer">
            <button class="btn btn-primary" data-dismiss="modal">Submit</button>
            <a href="#" @click="logout" data-dismiss="modal">
              <span>{{ $t('pages.userIconInHeader.signOut') }}</span>
            </a>
          </div>
        </div>
      </div>
    </div>

...

export default {
  name: 'test',
  data () {
    return {}
  },
  created () {
    // HERE I WOULD LIKE TO OPEN MODAL. If it's even possible?
    $(document).ready(function () {
      this.openModal()
    })
  },
  methods: {
    openModal () {
      $('#loginModal').modal('show')
    },

...

Answer 1

在没有mounted的情况下在$(document).ready(function(){})中使用：

mounted() {
  this.openModal();
},