我必须根据他们的区域,左边界或下边界对对象进行排序。当我想在它们的左边界或下边界上对它们进行排序时,我必须说排序x并排序y。当我想按区域排序时,我需要说排序。我试图通过切换方法这样做,但我不知道如何使用其中包含空字符串的switch方法。这就是我想要做的事情:
case "sort":
System.out.println("On what do you want to sort?");
String choice = scanner.nextLine();
switch (choice) {
case "x":
Arrays.sort(g, 0, lastPos, new Comparator < Geometric > () {
@Override
public int compare(Geometric o1, Geometric o2) {
if (o1.leftBorder() < o2.leftBorder()) {
return -1;
} else if (o1.leftBorder() > o2.leftBorder()) {
return 1;
} else {
return 0;
}
}
});
break;
case "y":
Arrays.sort(g, 0, lastPos, new Comparator < Geometric > () {
@Override
public int compare(Geometric o1, Geometric o2) {
if (o1.bottomBorder() < o2.bottomBorder()) {
return -1;
} else if (o1.bottomBorder() > o2.bottomBorder()) {
return 1;
} else {
return 0;
}
}
});
break;
case (""):
Arrays.sort(g, 0, lastPos, new Comparator < Geometric > () {
@Override
public int compare(Geometric o1, Geometric o2) {
if (o1.area() < o2.area()) {
return -1;
} else if (o1.area() > o2.area()) {
return 1;
} else {
return 0;
}
}
});
break;
default:
System.out.println("test1");
}
这是订购代码的更好方法(比如使用Comparator的工厂)但只是坚持你的代码我认为ENUM可以解决你的问题。
public enum CHOICES {
X, Y, AREA
}
private static CHOICES getChoice(String choice) {
if (choice == null || choice.trim().length() == 0) {
return CHOICES.AREA;
}
try {
return CHOICES.valueOf(choice.toUpperCase());
} catch (Exception e) {
// instead to check the value,
// if the input fir on, if not just catch the exception and return null
return null;
}
}
然后你可以像下面那样更换你的开关
//String choice = scanner.nextLine();
CHOICES choice = getChoice(scanner.nextLine());
switch (choice) {
case X:
//sort by X
break;
case Y:
//sort by Y
break;
case AREA:
//sort by area
break;
default:
System.out.println("test1");
}