Oracle sql函数输出语法

Question

我的输出有问题Portfolio_description为空，但我认为这并不重要我不知道语法是什么并传递两个输入参数P_Portfolio_number和P_Stock_Code

begin 
select Investor_Number,portfolio_description
into V_Investor_Number,V_portfolio_DES
from portfolio 
where P_Portfolio_number=Portfolio_Number;

select First_Name,Last_Name 
into V_firstname,V_Lastname 
from investor 
where Investor_Number=V_Investor_Number;

select Stock_name
into V_stock_name
from stock
where stock_code = P_Stock_Code;

select count(stock_code)
into V_count 
from transaction
where P_Stock_Code = stock_code and 
P_Portfolio_number=Portfolio_Number;

if V_count = 0 then
V_output := V_output || V_firstname||' '|| V_Lastname ||'does not exist ' || V_stock_name;
ELSIF  


that one work with the output 

某种程度上下面的一个不起作用

begin 
select Investor_Number,portfolio_description
into V_Investor_Number,V_portfolio_DES
from portfolio 
where P_Portfolio_number=Portfolio_Number;

select First_Name,Last_Name 
into V_firstname,V_Lastname 
from investor 
where Investor_Number=V_Investor_Number;

select Stock_name
into V_stock_name
from stock
where stock_code = P_Stock_Code;

select count(stock_code)
into V_count 
from transaction
where P_Stock_Code = stock_code and 
P_Portfolio_number=Portfolio_Number;

if V_count = 0 then
V_output := V_output || V_firstname||' '|| V_Lastname ||'does not exist ' || V_stock_name||'in the '||V_portfolio_DES;
ELSIF 

当我在末尾添加V_portfolio_DES时会引发其他异常

Answer 1

将引发其他例外

我假设您使用的是WHEN OTHERS。通常这是一个大错误。如果处理不当，请勿将其升高。您宁愿让Oracle显示正在发生的事情。使用您的“异常”，您什么也没做，只能成功地隐藏了错误原因。

无论如何：-当您将V_PORTFOLIO_DES添加到V_OUTPUT变量时，我的幸运猜测是V_OUTPUT被声明为VARCHAR2，但是

太小。例如：如果是

declare v_output varchar2(20);

并且第一段代码可以正常工作，因为变量的长度小于20个字符，但是-连接v_portfolio_des后，长度超过20并得到了错误。 
因此，请放大变量的大小。