C# .Net Framework 中 Gemini AI API 的 CURL 代码

Question

我正在 C# .net 框架中开发一个关于使用 Google Gemini API 制作人工智能的窗口应用程序。我在 CURL 中阅读了 google gemini api 的文档超过 10 遍。在 ChatGPT 的帮助下，我用 C# 编写了一些代码。这里看起来像：

using System;
using System.IO;
using System.Net.Http;
using System.Net.Http.Headers;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;

namespace KJAI
{
    public partial class Form1 : Form
    {
        private string apiKey = "YOUR_API_KEY";

        public Form1()
        {
            InitializeComponent();
        }

        private async void button1_Click(object sender, EventArgs e)
        {
            string userInput = textBox1.Text;

            string output = await SendRequestAndGetResponse(userInput);

            output = output.Replace("\\n", Environment.NewLine)
                           .Replace("\n", "")
                           .Replace("**", "");

            richTextBox1.Text = output;
        }

        private async Task<string> SendRequestAndGetResponse(string userInput)
        {
            string jsonBody = $@"{{
                ""contents"": [
                    {{
                        ""role"": """",
                        ""parts"": [
                            {{
                                ""text"": ""{userInput}""
                            }}
                        ]
                    }}
                ],
                ""generationConfig"": {{
                    ""temperature"": 0.9,
                    ""topK"": 50,
                    ""topP"": 0.95,
                    ""maxOutputTokens"": 4096,
                    ""stopSequences"": []
                }},
                ""safetySettings"": [

                ]
            }}";

            using var client = new HttpClient();
            var request = new HttpRequestMessage(HttpMethod.Post, $"https://generativelanguage.googleapis.com/v1beta/models/gemini-1.0-pro:generateContent?key={apiKey}");
            request.Content = new StringContent(jsonBody, Encoding.UTF8);
            request.Content.Headers.ContentType = new MediaTypeHeaderValue("application/json");

            var response = await client.SendAsync(request).ConfigureAwait(false);

            if (response.IsSuccessStatusCode)
            {
                string responseBody = await response.Content.ReadAsStringAsync();
                return responseBody.Substring(responseBody.IndexOf("\"text\": \"") + 9, responseBody.IndexOf("\"", responseBody.IndexOf("\"text\": \"") + 10) - responseBody.IndexOf("\"text\": \"") - 9);
            }
            else
            {
                return $"Error: {response.StatusCode} - {response.ReasonPhrase}";
            }
        }
    }
}

但是，我想让 Gemini 能够记住用户和人工智能之前的对话，但我不知道该怎么做。大家有想法吗？

我尽力建立用户和ai之间的聊天记录并将其制成字典形式，但我失败了。让人工智能能够访问并记住他们的对话非常重要。

Answer 1

字符串 googleaikey = "**6oY"; RestClient 客户端 = new RestClient("https://generativelanguage.googleapis.com/v1beta/models/gemini-1.0-pro:generateContent?key="+googleaikey+ ""); RestRequest 请求 = new RestRequest() { Method = Method.Post }; ServicePointManager.SecurityProtocol = SecurityProtocolType.Tls12; // .NET 4.5 ServicePointManager.SecurityProtocol = (SecurityProtocolType)3072; // .NET 4.0 request.AddParameter("Content-Type", "application/json", ParameterType.GetOrPost); // 使用消息和其他参数创建请求正文

        string requestBody = @"{{
            ""contents"": [
                {{
                    ""role"": ""user"",
                    ""parts"": [
                        {{
                            ""text"":"+ userInput+ @"
                        }}
                    ]
                }}
            ],
            ""generationConfig"": {{
                ""temperature"": 0.9,
                ""topK"": 50,
                ""topP"": 0.95,
                ""maxOutputTokens"": 4096,
                ""stopSequences"": []
            }},
            ""safetySettings"": [

            ]
        }}";

        // Add the JSON body to the request
        request.AddJsonBody(JsonConvert.SerializeObject(requestBody));
        RestResponse response = client.Execute(request);
        var contents = response.Content;

不工作“错误”无效参数 400