使用python替换.bat文件中的行

Question

我是python的新手，在处理.bat文件时卡住了

1）我有一个.bat文件，其中包含以下几行：

set local_dir=%~d0%~p0

set LVMain_StartAddress=0xfaff
set LVMain_EndAddress=0x0f4ff
set HVMain_StartAddress=0x01d00
set HVMain_EndAddress=0x095ff
set LVMain_StartAddressMerged=0x0D000
set LVMain_EndAddressMerged=0x0fcff
set HVMain_StartAddressMerged=0x01001d00
set HVMain_EndAddressMerged=0x010095dd

2）python脚本遍历该文件以查找行“ set LVMain_StartAddress=0xfaff”

3）找到行后，我想用一个新的十六进制地址替换它。有时新的十六进制地址为5个字符长

4）下面是我为此编写的python代码：

# write LVMain start address in .bat file
with open("..\..\..\Tools\Scripts\GenerateRomTestChecksums.bat", "r+") as f:

    #read lines individually until we find where to write LvMain Start address
    BatFileLine = f.readline()
    while( (LVMain_StartPattern in BatFileLine ) == False ):
        BatFileLine = f.readline()

    #set marker back to the beginning of the line
    LineMarker = int(f.tell()) - (int(len(BatFileLine)) + 0x01)
    f.seek(LineMarker)

    #split string where address starts to write new address in file
    name, hex_address = BatFileLine.split('0x')
    #append new address and carriage return
    name = name + APPL_End_address + "\n"
    print(len(name))


    contents = f.read(len(BatFileLine)).replace(BatFileLine,name)
    f.seek(LineMarker)
    f.write(name)

这是较大函数的一部分，并且“ APPL_End_address”作为参数提供

5）当我运行此代码，并且新的十六进制地址为5个十六进制数字宽时，我得到以下输出：

似乎新的十六进制地址已正确写入，但下一行的第一个字符已删除。有什么想法吗？

Answer 1

尝试一下，简单得多。

with open("Fileout.txt",'w') as f:
for line in inputFile:
    if "LVMain_StartAddress=" in line:
        line = line.replace(line.split("=")[1],APPL_End_address)
        f.write("%s\n" % line)
    else:
        f.write("%s" % line)