自动缩放组中发生某些更改或创建新实例时如何收到通知

Question

我正在尝试编写一个自动化脚本（在 trypscript 中）升级 AMI 映像，为此我会将实例数量加倍（即在自动缩放组中进行缩放），这样我就可以得到与新 AMI 映像完全相同数量的新实例，然后我将在新实例上部署我的应用程序，但我不知道新实例何时准备就绪，aws ec2 sdk 或 aws 自动缩放组内是否有回调通知程序

此刻我正在努力

const timer = setTimeout(() => { if (newInstanceIds.length >= currentDesiredNumberOfInstances) clearTimeout(timer) const asgAfterUpdate = await getAutoScalingGroup(asgName,credentials,region); const allInstances = {}.AutoScalingGroups![0].Instances; if (allInstances.length >= myNewScalingSize) clearTimeout(timer) }, 10000);

这些是我正在尝试使用的sdk (@aws-sdk/client-auto-scaling": "^3.635.0", "@aws-sdk/client-ec2": "^3.620.0"

Answer 1

您可以使用 waitUntilInstanceStatusOk

轮询 EC2 实例的状态

类似这样的事情：

import { EC2Client, DescribeInstanceStatusCommand, waitUntilInstanceStatusOk } from "@aws-sdk/client-ec2";
import { AutoScalingClient, DescribeAutoScalingGroupsCommand } from "@aws-sdk/client-auto-scaling";

const ec2Client = new EC2Client({ region });
const asgClient = new AutoScalingClient({ region });

async function waitForInstances(asgName: string, desiredCount: number) {
    let ready = false;
    while (!ready) {
        const asgResponse = await asgClient.send(new DescribeAutoScalingGroupsCommand({ AutoScalingGroupNames: [asgName] }));
        const instances = asgResponse.AutoScalingGroups?.[0].Instances || [];

        // Filter out instances that are still pending
        const instanceIds = instances.filter(instance => instance.LifecycleState === 'InService').map(instance => instance.InstanceId);

        if (instanceIds.length >= desiredCount) {
            ready = true;
            // Wait for all instances to pass status checks
            for (const instanceId of instanceIds) {
                await waitUntilInstanceStatusOk({ client: ec2Client, maxWaitTime: 300, minDelay: 10 }, { InstanceIds: [instanceId] });
            }
        } else {
            await new Promise(res => setTimeout(res, 10000)); // Wait 10 seconds before polling again
        }
    }
}