以下程序在屏幕上不打印任何内容的情况下运行,可能是因为循环超过了空字符。我无法理解为什么以及如何发生这种情况,以及如何解决它。
//program to find how many word in the text doesn't contain p char
#include<stdio.h>
#include<stdbool.h>
#define space ' '
void find_word(char s[]) {
bool wordfound = false;
int i, j = 0, word = 0;
i = 0;
while (s[i]) { //s[i]!='\0' does not
if (s[i] != 'p' && s[i + 1] != space) { //for the first word
wordfound = true;
word++;
}
wordfound = false;
if (s[i] == space && s[i + 1] != space) { //for more than one word in the text
for (j = i + 1; s[j] != space; j++)
if (s[j] != 'p' && s[j + 1] != space)
wordfound = true;
}
if (wordfound) {
word++;
}
wordfound = false;
i = j;
i++;
} //end while loop
printf("Number of words not contain p character%d\n\n", word);
}
int main(void) {
char s[] = {"pppp zzzz ppp ssss dfg sfsfdsf"};
find_word(s);
return 0;
}
这段代码存在一些问题,但主要的一点是在循环内部将j分配给i会导致无限循环,因为while(s [i])条件永远不会满足。你为什么不试着简单,如下:
//program to find how many word in the text doesn't contain p char
#include<stdio.h>
#include<stdbool.h>
#define space ' '
void find_word(char s[]) {
bool is_in = false;
short words_count = 0, i = 0;
while (s[i]) {
if (s[i] == 'p') { // if this letter is a 'p', mark the word
is_in = true;
}
if (s[i] == space) { // if it's end of word
if (!is_in) { // check if 'p' is present and increase the count
words_count++;
}
is_in = false;
}
i++;
}
if (!is_in) { // check if the last word has 'p'
words_count++;
}
printf("no. of words without p is %d\n", words_count);
}
int main(void) {
char s[] = {"pppp zzzz ppp ssss dfg sfsfdsf"};
find_word(s);
return 0;
}
根据您的输入,您似乎将for-loop
终止条件设置为不可满足。
if (s[i] == space && s[i + 1] != space) { //for more than one word in the text
for (j = i + 1; s[j] != space; j++)
if (s[j] != 'p' && s[j + 1] != space)
wordfound = true;
}
在这里,您要检查输入字符串中的前导空格。如果找到它,则递增索引检查,直到到达另一个空格。如果你的字符串没有尾随空格怎么办?
而是尝试使用null和space的第二个条件来终止循环:
if (s[i] == space && s[i + 1] != space) { //for more than one word in the text
for (j = i + 1; s[j] != '\0' && [j] != space; j++)
if (s[j] != 'p' && s[j + 1] != space)
wordfound = true;
}
然后你设置:
wordfound = false;
i = j;
i++;
} //end while loop
这将继续重新设置你的循环,我不清楚你的推理,但这将无限期地运行你的循环。
如果您进行这些编辑,您的代码将终止:
#include<stdio.h>
#include<stdbool.h>
#define space ' '
void find_word(char s[]) {
bool wordfound = false;
int i, j = 0, word = 0;
i = 0;
while (s[i]) { //s[i]!='\0' does not
if (s[i] != 'p' && s[i + 1] != space) { //for the first word
wordfound = true;
word++;
}
wordfound = false;
if (s[i] == space && s[i + 1] != space) { //for more than one word in the text
for (j = i + 1; s[j] && s[j] != space; j++)
if (s[j] != 'p' && s[j + 1] != space)
wordfound = true;
}
if (wordfound) {
word++;
}
wordfound = false;
i++;
} //end while loop
printf("Number of words not contain p character%d\n\n", word);
}
int main(void) {
char s[] = {"pppp zzzz ppp ssss dfg sfsfdsf"};
find_word(s);
return 0;
}
输出:
Number of words not contain p character24