我正在尝试使用python和美丽的汤来提取下面标签的内容部分:
<meta property="og:title" content="Super Fun Event 1" />
<meta property="og:url" content="http://superfunevents.com/events/super-fun-event-1/" />
我正在使用BeautifulSoup来加载页面并找到其他东西(这也从源代码中隐藏的id标签中获取文章id),但我不知道正确的方法来搜索html并找到这些位,我尝试过find和findAll的变种无济于事。代码迭代目前的网址列表...
#!/usr/bin/env python
# -*- coding: utf-8 -*-
#importing the libraries
from urllib import urlopen
from bs4 import BeautifulSoup
def get_data(page_no):
webpage = urlopen('http://superfunevents.com/?p=' + str(i)).read()
soup = BeautifulSoup(webpage, "lxml")
for tag in soup.find_all("article") :
id = tag.get('id')
print id
# the hard part that doesn't work - I know this example is well off the mark!
title = soup.find("og:title", "content")
print (title.get_text())
url = soup.find("og:url", "content")
print (url.get_text())
# end of problem
for i in range (1,100):
get_data(i)
如果有人可以帮我排序,找到og:title和og:内容真棒!
提供meta
标记名称作为find()
的第一个参数。然后,使用关键字参数检查特定属性:
title = soup.find("meta", property="og:title")
url = soup.find("meta", property="og:url")
print(title["content"] if title else "No meta title given")
print(url["content"] if url else "No meta url given")
如果您知道title和url meta属性将始终存在,则此处的if
/ else
检查将是可选的。
试试这个 :
soup = BeautifulSoup(webpage)
for tag in soup.find_all("meta"):
if tag.get("property", None) == "og:title":
print tag.get("content", None)
elif tag.get("property", None) == "og:url":
print tag.get("content", None)