如何将txt文件中的值存储为整数C

Question

我正在尝试编写一个函数，从 txt 文件导入数据并将它们存储在结构数组中。

txt 文件如下所示：

1040,2024,2,29,13,0
1112,2027,3,12,13,0
1048,2026,6,20,10,30
1080,2024,2,29,10,30
1104,2026,6,9,14,0
1088,2024,2,29,11,30
1104,2024,2,29,14,0
1112,2024,2,29,12,0
1056,2025,2,28,11,30
1024,2024,2,29,10,0
1032,2024,2,29,13,30
1120,2024,2,29,11,0
1112,2027,3,10,11,0
1128,2024,2,29,12,30
1024,2027,3,12,10,30

但是当我尝试使用 sscanf 时，它们只是读为 0...这是我的函数：

int importNumbers(const char* datafile, struct Appointment appoints[], int max) {

    int Num = 0;

    FILE* fp= fopen(datafile, "r");

    if (fp != NULL)
    {
        char line[100];
        while (Num < max && fgets(line, sizeof(line), fp) != NULL) {
            sscanf(&appNum, "%d,%d,%d,%d,%d,%d",
                &appoints[Num].patientNumber,
                &appoints[Num].date.year,
                &appoints[Num].date.month,
                &appoints[Num].date.year,
                &appoints[Num].time.hour,
                &appoints[Num].time.min);

            Num++;
        }

        fclose(fp);
    }

    return Num; 
}

Answer 1

警告：如果没有更多[发布]代码，我必须综合

struct

定义。

并且，来自我的最高评论：

你这样做

&AppNum

但它没有定义。您的意思是：

line

？

此外，您还使用

date.year

两次。第二个应该是

date.day

---

更正此问题并添加打印代码，这是更正后的代码：

#include <stdio.h>

struct date {
    int year;
    int month;
    int day;
};

struct time {
    int hour;
    int min;
};

struct Appointment {
    int patientNumber;
    struct date date;
    struct time time;
};

struct Appointment apptlist[50];

int
importNumbers(const char *datafile, struct Appointment appoints[], int max)
{

    int Num = 0;

    FILE *fp = fopen(datafile, "r");

    if (fp != NULL) {
        char line[100];

        while (Num < max && fgets(line, sizeof(line), fp) != NULL) {
#if 0
            sscanf(&appNum,
#else
            sscanf(line,
#endif
                "%d,%d,%d,%d,%d,%d",
                &appoints[Num].patientNumber,
                &appoints[Num].date.year,
                &appoints[Num].date.month,
#if 0
                &appoints[Num].date.year,
#else
                &appoints[Num].date.day,
#endif
                &appoints[Num].time.hour,
                &appoints[Num].time.min);

            Num++;
        }

        fclose(fp);
    }

    return Num;
}

#define PRT(_sym) \
    printf(" " #_sym "=%d",appt->_sym)

int
main(void)
{

    int tot = importNumbers("data.txt",
        apptlist,sizeof(apptlist) / sizeof(apptlist[0]));
    printf("tot=%d\n",tot);

    for (struct Appointment *appt = apptlist;  appt < &apptlist[tot];  ++appt) {
        PRT(patientNumber);
        PRT(date.year);
        PRT(date.month);
        PRT(date.day);
        PRT(time.hour);
        PRT(time.min);
        printf("\n");
    }

    return 0;
}

---

在上面的代码中，我使用

cpp

条件来表示旧代码与新代码：

#if 0
// old code
#else
// new code
#endif

#if 1
// new code
#endif

注意：这可以通过运行文件来清理

unifdef -k

---

对于给定的数据文件输入，以下是程序输出：

tot=15
 patientNumber=1040 date.year=2024 date.month=2 date.day=29 time.hour=13 time.min=0
 patientNumber=1112 date.year=2027 date.month=3 date.day=12 time.hour=13 time.min=0
 patientNumber=1048 date.year=2026 date.month=6 date.day=20 time.hour=10 time.min=30
 patientNumber=1080 date.year=2024 date.month=2 date.day=29 time.hour=10 time.min=30
 patientNumber=1104 date.year=2026 date.month=6 date.day=9 time.hour=14 time.min=0
 patientNumber=1088 date.year=2024 date.month=2 date.day=29 time.hour=11 time.min=30
 patientNumber=1104 date.year=2024 date.month=2 date.day=29 time.hour=14 time.min=0
 patientNumber=1112 date.year=2024 date.month=2 date.day=29 time.hour=12 time.min=0
 patientNumber=1056 date.year=2025 date.month=2 date.day=28 time.hour=11 time.min=30
 patientNumber=1024 date.year=2024 date.month=2 date.day=29 time.hour=10 time.min=0
 patientNumber=1032 date.year=2024 date.month=2 date.day=29 time.hour=13 time.min=30
 patientNumber=1120 date.year=2024 date.month=2 date.day=29 time.hour=11 time.min=0
 patientNumber=1112 date.year=2027 date.month=3 date.day=10 time.hour=11 time.min=0
 patientNumber=1128 date.year=2024 date.month=2 date.day=29 time.hour=12 time.min=30
 patientNumber=1024 date.year=2027 date.month=3 date.day=12 time.hour=10 time.min=30