这个问题在这里已有答案：
我很抱歉，如果我遗漏了一些明显的东西，比如“而不是”，但我尝试了许多不同的方式，它仍然做同样的事情，即显示实际的javascript代码，而不是功能，当我把它放在一个。 html文件或给我这个错误：解析错误：语法错误，在第9行的E：\ XAMPP \ htdocs \ website2 \ test.php中出现意外的'<'当我将它放在php文件中时。
这是代码：
<!DOCTYPE html>
<html>
<head>
<script src="js.js" type="text/javascript"></script>
<title>TEST</title>
</head>
<body>
<?php
echo '<script type="text/javascript">
var https = require("https");
var username = "04d2ac7f76a0fbc0eee9dc5ef96b9259";
var password = "dc70ffc7ad911236bc2e0822855e2d42";
var auth = "Basic " + new Buffer(username + ':' + password).toString('base64');
var request = https.request({
method: "GET",
host: "api.intrinio.com",
path: "/companies?ticker=AAPL",
headers: {
"Authorization": auth
}
}, function(response) {
var json = "";
response.on('data', function (chunk) {
json += chunk;
});
response.on('end', function() {
var company = JSON.parse(json);
console.log(company);
});
});</script>';
?>
</body>
</html>
为什么不在没有php标签的情况下呢？该错误是因为您没有转义代码中的单引号。
没有PHP的例子：
<!DOCTYPE html>
<html>
<head>
<script src="js.js" type="text/javascript"></script>
<title>TEST</title>
</head>
<body>
<script type="text/javascript">
var https = require("https");
var username = "04d2ac7f76a0fbc0eee9dc5ef96b9259";
var password = "dc70ffc7ad911236bc2e0822855e2d42";
var auth = "Basic " + new Buffer(username + ':' + password).toString('base64');
var request = https.request({
method: "GET",
host: "api.intrinio.com",
path: "/companies?ticker=AAPL",
headers: {
"Authorization": auth
}
}, function(response) {
var json = "";
response.on('data', function (chunk) {
json += chunk;
});
response.on('end', function() {
var company = JSON.parse(json);
console.log(company);
});
});</script>
</body>
</html>
用php的例子：
<!DOCTYPE html>
<html>
<head>
<script src="js.js" type="text/javascript"></script>
<title>TEST</title>
</head>
<body>
<?php
echo '<script type="text/javascript">
var https = require("https");
var username = "04d2ac7f76a0fbc0eee9dc5ef96b9259";
var password = "dc70ffc7ad911236bc2e0822855e2d42";
var auth = "Basic " + new Buffer(username + ':' + password).toString(\'base64\');
var request = https.request({
method: "GET",
host: "api.intrinio.com",
path: "/companies?ticker=AAPL",
headers: {
"Authorization": auth
}
}, function(response) {
var json = "";
response.on(\'data\', function (chunk) {
json += chunk;
});
response.on(\'end\', function() {
var company = JSON.parse(json);
console.log(company);
});
});</script>';
?>
</body>
</html>
但更重要的是这是一个node.js代码而不是客户端javascript。我建议你得到一些node和javascript教程。
你应该在你的代码中逃避'in with'。
正如伊万所指出的那样，你怀疑自己已经把'和'置于不合适的地方而没有逃脱。
<!DOCTYPE html>
<html>
<head>
<script src="js.js" type="text/javascript"></script>
<title>TEST</title>
</head>
<body>
<?php
echo '<script type="text/javascript">
var https = require("https");
var username = "04d2ac7f76a0fbc0eee9dc5ef96b9259";
var password = "dc70ffc7ad911236bc2e0822855e2d42";
var auth = "Basic " + new Buffer(username + \':\' + password).toString(\'base64\');
var request = https.request({
method: "GET",
host: "api.intrinio.com",
path: "/companies?ticker=AAPL",
headers: {
"Authorization": auth
}
}, function(response) {
var json = "";
response.on(\'data\', function (chunk) {
json += chunk;
});
response.on(\'end\', function() {
var company = JSON.parse(json);
console.log(company);
});
});</script>';
?>
</body>
Echo函数用于输出字符串，并且您正在回显不是有效字符串的代码语句。将其作为单行放置为：
<?php echo '<script type="text/javascript">var https = require("https");var username = "04d2ac7f76a0fbc0eee9dc5ef96b9259";var password = "dc70ffc7ad911236bc2e0822855e2d42";var auth = "Basic " + new Buffer(username + ':' + password).toString(\'base64\');var request = https.request({method: "GET",host: "api.intrinio.com",path: "/companies?ticker=AAPL",headers: {"Authorization": auth}}, function(response) {var json = "";response.on(\'data\', function (chunk) {json += chunk;});response.on(\'end\', function() {var company = JSON.parse(json);console.log(company);});});</script>';?>