我完全被这项任务困住了。我首先在 int main() 中编写了所有内容,没有任何问题。一切都很顺利!不幸的是,我们的讲师希望将其拆分为多个函数(每个函数少于 35 行)。我已经将其分开,如下所示,但不幸的是我对函数和传递/引用它们的了解(谷歌并没有多大帮助)并不是那么高。我的程序现在根本无法运行。所有“书籍”都会给出错误,所以我不确定我是否错误地传递了结构或数组。请帮忙!
原始txt文件内容如下:
number of books
title
author
price
title
author
price
代码:
#include <iostream>
#include <fstream>
#include <string>
#include <iomanip>
using namespace std;
void setStruct() {
struct bookTable {
string title;
string author;
double price;
};
}
void setArray(int &arraySize, struct bookTable *Book[]) {
ifstream infile;
int bookCounter = 0;
infile.open("books2.txt");
if (!infile) {
cout << "Unable to open Books.txt" << endl;
}
infile >> arraySize;
infile.ignore(100, '\n');
bookTable *Book = new bookTable[arraySize];
infile.close();
}
void readFile(struct bookTable *Book[]) {
ifstream infile;
int bookCounter = 0;
infile.open("books2.txt");
for (int i = 0; getline(infile, Book[i].title); i++) {
getline(infile, Book[i].author, '\n');
infile >> Book[i].price;
infile.ignore(100, '\n');
bookCounter++;
}
infile.close();
}
void displayMenu(struct bookTable *Book[]) {
int menuChoice = 0, bookCounter = 0;
string findTitle;
do { cout << "\n===== Bookstore App =====" << endl;
cout << "1. Print Books" << endl;
cout << "2. Change Price" << endl;
cout << "3. Quit" << endl;
cout << "\nEnter Choice: ";
cin >> menuChoice;
if (menuChoice == 1) {
for (int i = 0; i < bookCounter; i++) {
cout << "===== BOOK =====" << endl;
cout << "Title: " << Book[i].title << endl;
cout << "Author: " << Book[i].author << endl;
cout << "Price: " << fixed << setprecision(2) << Book[i].price << endl; } }
else if (menuChoice == 2) { cin.ignore(100, '\n');
cout << "What is the title of the book? ";
getline(cin, findTitle, '\n');
for (int i = 0; i < bookCounter; i++) {
if (findTitle == Book[i].title) {
cout << "Enter New Price: " << endl;
cin >> Book[i].price;
}
else if (findTitle != Book[i].title) {
cout << "Unable to find Book" << endl;
}}}
else if (menuChoice < 1 || menuChoice > 3) {
cout << "Invalid Entry. Please enter 1, 2, or 3 from the options menu." << endl;
} } while (menuChoice != 3);
}
void writeFile(int arraySize, struct bookTable *Book[]) {
ofstream outfile;
int bookCounter = 0;
outfile.open("sale2.txt");
outfile << arraySize << endl;
for (int i = 0; i < bookCounter; i++) {
outfile << Book[i].title << endl;
outfile << Book[i].author << endl;
outfile << fixed << setprecision(2) << Book[i].price << endl;
}
outfile.close();
delete[] Book;
}
int main() {
setStruct();
setArray();
readFile();
displayMenu();
writeFile();
cout << "\nSale2.txt has been created." << endl;
return 0;
}
我还没有编译或运行这个,但希望它能让你朝着正确的方向开始:
#include <iostream>
#include <fstream>
#include <string>
#include <iomanip>
using namespace std;
// This declares "struct bookTable"
// You need to actually define a variable of this type later in your program
struct bookTable {
string title;
string author;
double price;
};
bookTable * setArray(int &arraySize, struct bookTable *Book[]) {
ifstream infile;
int bookCounter = 0;
infile.open("books2.txt");
if (!infile) {
cout << "Unable to open Books.txt" << endl;
}
infile >> arraySize;
infile.ignore(100, '\n');
bookTable *Book = new bookTable[arraySize];
infile.close();
// This returns an empty array of bookTable[]
return Book;
}
void readFile(struct bookTable *Book) {
ifstream infile;
int bookCounter = 0;
infile.open("books2.txt");
for (int i = 0; getline(infile, Book[i].title); i++) {
getline(infile, Book[i].author, '\n');
infile >> Book[i].price;
infile.ignore(100, '\n');
bookCounter++;
}
infile.close();
}
void displayMenu(struct bookTable *Book[]) {
int menuChoice = 0, bookCounter = 0;
string findTitle;
do { cout << "\n===== Bookstore App =====" << endl;
cout << "1. Print Books" << endl;
cout << "2. Change Price" << endl;
cout << "3. Quit" << endl;
cout << "\nEnter Choice: ";
cin >> menuChoice;
if (menuChoice == 1) {
for (int i = 0; i < bookCounter; i++) {
cout << "===== BOOK =====" << endl;
cout << "Title: " << Book[i].title << endl;
cout << "Author: " << Book[i].author << endl;
cout << "Price: " << fixed << setprecision(2) << Book[i].price << endl; } }
else if (menuChoice == 2) { cin.ignore(100, '\n');
cout << "What is the title of the book? ";
getline(cin, findTitle, '\n');
for (int i = 0; i < bookCounter; i++) {
if (findTitle == Book[i].title) {
cout << "Enter New Price: " << endl;
cin >> Book[i].price;
}
else if (findTitle != Book[i].title) {
cout << "Unable to find Book" << endl;
}}}
else if (menuChoice < 1 || menuChoice > 3) {
cout << "Invalid Entry. Please enter 1, 2, or 3 from the options menu." << endl;
} } while (menuChoice != 3);
}
// !!! DON'T UNCOMMENT THIS UNTIL YOU FIGURE OUT HOW TO PRESERVE "arraySize" !!!
// Suggestion: use a C++ "vector<>" instead of an array...
// void writeFile(int arraySize, struct bookTable *Book[]) {
//
// ofstream outfile;
// int bookCounter = 0;
//
// outfile.open("sale2.txt");
//
// outfile << arraySize << endl;
//
// for (int i = 0; i < bookCounter; i++) {
//
// outfile << Book[i].title << endl;
// outfile << Book[i].author << endl;
// outfile << fixed << setprecision(2) << Book[i].price << endl;
// }
//
// outfile.close();
//
// delete[] Book;
//
// }
int main() {
// setStruct(); // Not needed
struct bookTable *book_table = setArray(); // Allocate space
readFile(book_table); // Initialize data
displayMenu(book_table); // use book_table
// writeFile(); // TBD
cout << "\nSale2.txt has been created." << endl;
return 0;
}
要点:
当“main()”中包含所有内容时,所有代码都可以看到所有变量。
当您将所有内容移至单独的函数中时,函数将无法再“看到”这些变量。
这称为“范围”
有几件事:
-您的结构不需要位于 setStruct 函数内部,setStruct 应该用于将数据发送到现有结构(下面的示例)
-setArray 在调用时没有传递任何参数(它需要
(int &arraySize, struct bookTable *Book[])
),其他一些函数也没有传递任何参数,这意味着它们实际上没有任何数据可以修改。setArray(size of array, struct being passed to it);
另外,还有一个关于如何单独定义 setStruct 和结构体的示例:
struct bookTable {
string title;
string author;
double price;
};
void setStruct(&struct x, string title, string author, double price) {
x.title = title;
x.author = author;
x.price = price;
}
确保注意每个函数的作用,以便您知道要传递给它们的参数并更好地理解整体代码。
通过将 main() 拆分为一堆函数,除了使代码模块化且易读之外,您实际上并没有做太多事情
此外,发布您遇到的确切错误也会有所帮助,因为我想即使您修复了我提到的这些问题,我也可能无法完美工作
void setStruct() {
struct bookTable {
string title;
string author;
double price;
};
}
您创建一个函数
setStruct()
,然后在其他函数中多次使用它,而无需访问该函数本身。为什么不将结构体放在其全局作用域中,这样您就可以在
Main()
或其他任何地方使用它,并在函数之间自由传递结构体声明?还有:
for (int i = 0; getline(infile, Book[i].title); i++) {
getline(infile, Book[i].author, '\n');
infile >> Book[i].price;
infile.ignore(100, '\n');
bookCounter++;
}
您传递一个 use
Book
,就好像它在您声明它并可能定义它的范围内一样。但是,您通过函数传递它 - 这意味着结构类型现在超出范围,需要通过指针访问其元素。所以你的代码需要这样调整:
void readFile(struct bookTable *Book[]) {
ifstream infile;
int bookCounter = 0;
infile.open("books2.txt");
for (int i = 0; getline(infile, Book[i]->title); i++) {
getline(infile, Book[i]->author, '\n');
infile >> Book[i]->price;
infile.ignore(100, '\n');
bookCounter++;
}
infile.close();
}
请注意,您曾经
Book[i].variable
的每个地方现在都是
Book[i]->variable
- 希望这会有所帮助。