PyQt4:当选中一个复选框时,如果还检查了另一个复选框,则按一个按钮从LineEdit打印一些文本

问题描述 投票:1回答:1
import sys, os
import PyQt4
from PyQt4 import QtGui, QtCore 
from PyQt4.QtCore import *
from PyQt4.QtGui import *

class Tab1Widget1(QWidget):
    def __init__(self, parent=None):
        super().__init__()

        self.Tab1Widget1initUI()

        self.bridge = Tab1Widget2()

    def Tab1Widget1initUI(self):
        self.setLayout(QGridLayout())

        self.T1W1_checkbox = QCheckBox('checkbox1', self)
        self.layout().addWidget(self.T1W1_checkbox, 1, 0)

    def test(self):
        print ('123')


    def run(self):
        if self.T1W1_checkbox.isChecked() == True:
            self.test()
            if self.bridge.T1W2_checkbox.isChecked() == True:
                print (self.bridge.T1W2_le.text())

class Tab1Widget2(QWidget):

    def __init__(self, parent=None):
        super().__init__()
        self.setLayout(QGridLayout())

        self.T1W2_checkbox = QCheckBox('checkbox2', self)
        self.layout().addWidget(self.T1W2_checkbox, 0, 0)

        self.T1W2_le = QLineEdit()
        self.layout().addWidget(self.T1W2_le, 0, 1)

class Tab1Layout(QWidget):
    def __init__(self, parent=None):
        super().__init__()
        self.setLayout(QGridLayout())

        self.group1 = Tab1Widget1(self)
        scroll = QScrollArea(self)
        scroll.setWidget(self.group1)
        scroll.setWidgetResizable(True)
        self.layout().addWidget(scroll, 0, 0)

        self.group2 = Tab1Widget2(self)
        self.layout().addWidget(self.group2, 1, 0)

        self.btnRun = QPushButton('Run', self)
        self.layout().addWidget(self.btnRun, 3, 0)
        self.btnRun.clicked.connect(self.group1.run)


class Page1(QTabWidget):
    def __init__(self, parent=None):
        super().__init__()
        self.tab1 = Tab1Layout()
        self.addTab(self.tab1, "Tab1")

        self.tab2 = QWidget()
        self.tab3 = QWidget()
        self.addTab(self.tab2, "Tab2")
        self.addTab(self.tab3, "Tab3")
        self.tab2_initUI()
        self.tab3_initUI()

    def tab2_initUI(self):
        grid = QGridLayout()
        self.tab2.setLayout(grid)

    def tab3_initUI(self):
        grid = QGridLayout()
        self.tab3.setLayout(grid)

class MainWindow(QMainWindow):
    def __init__(self, parent=None):
        super().__init__()
        self.setGeometry(450, 250, 800, 550)
        self.startPage1()

    def startPage1(self):
        x = Page1(self)
        self.setWindowTitle("Auto Benchmark")
        self.setCentralWidget(x)
        self.show()

def main():
    app = QApplication(sys.argv)
    main = MainWindow()
    main.show()
    sys.exit(app.exec_())


if __name__ == '__main__':
    main()

如果检查checkbox1并按run按钮,它将打印123。但是,通过按run按钮,我希望checkbox2也打印一些在lineedit中输入的文本,如果checkbox1也被检查(即它应首先打印123然后打印456)。

我查了一些类似的问题,但没有一个提供正确的答案。如果有人知道如何解决它,请让我知道谢谢!

python pyqt pyqt4 qcheckbox
1个回答
0
投票

问题是你正在创建几个Tab1Widget2,你在Tab1Layout中创建的第一个,也就是你看到的那个,然后你在Tab1Widget1中创建了另一个,但没有时间,因为你没有通过父,如果你通过它将** **作为父母,您将观察到以下内容:

self.bridge = Tab1Widget2(self)

enter image description here

这不是你想要的,所以不是创建一个新的,你必须传递已经存在的那个,一个选项是通过构造函数传递它:

class Tab1Widget1(QWidget):
    def __init__(self, bridge, parent=None): # Modify here
        super().__init__(parent)
        self.Tab1Widget1initUI()
        self.bridge = bridge  #Modify here

    # ...

    def test(self): print ('123')

    def run(self):
        if self.T1W1_checkbox.isChecked():
            self.test()
            if self.bridge.T1W2_checkbox.isChecked():
                print (self.bridge.T1W2_le.text())

class Tab1Widget2(QWidget):
    # ...

class Tab1Layout(QWidget):
    def __init__(self, parent=None):
        super().__init__()
        self.setLayout(QGridLayout())

        self.group2 = Tab1Widget2(self) # Modify here
        self.group1 = Tab1Widget1(self.group2, self) # Modify here
        scroll = QScrollArea(self)
        scroll.setWidget(self.group1)
        scroll.setWidgetResizable(True)
        self.layout().addWidget(scroll, 0, 0)

        # self.group2 = Tab1Widget2(self) # Modify here
        self.layout().addWidget(self.group2, 1, 0)

        # ...
© www.soinside.com 2019 - 2024. All rights reserved.