花蟒-制作更多花

Question

所以我正在制作这个程序，其中花朵刚刚出现，然后你设置花瓣的数量。它还有另外两个输出，即另一朵不同颜色的花，以及一颗充满颜色的星星。我被这段代码困住了，因为我试图让多朵花出现在第一个输出中，但如果笔不与绘制的第一朵花重叠，我就无法得到它。

#Code Notes: You want three outputs. The flower (not filled), a filled 
flower with 6 different colors, and a spiraled star

#importing sys and turtle.
import sys
import turtle


#function for flower shape
def draw_square(square):
   for i in range(0,2):
      square.forward(100)
      square.right(70)
      square.forward(100)
      square.right(110)

#function to draw the flower
def draw_flower(petalNumber):
   window = turtle.Screen()
   window.bgcolor("beige")
   window.title("Flower")
#flower turtle
   flower = turtle.Turtle()
   flower.shape("triangle")
   flower.color("teal")
   flower.pencolor("beige")
   flower.pensize(3)

   flower.goto(15,70)
   flower = "teal"
   for number in range(0, petalNumber):
      flower.begin_fill()
      draw_square(flower)
      flower.end_fill()
      flower.right(360.0/petalNumber)

window.exitonclick() #when clicked the window closes

#function for colorful art (the petals are filled in with different colors)
def colorfulArt(numberOfPetals):
   colors = ["red","blue","green","orange","pink","teal","purple","yellow"]
   window = turtle.Screen()
   window.bgcolor("white")
   window.title("Pinwheel Flower")

   flower = turtle.Turtle()
   flower.shape("triangle")
   flower.color("blue")

   for petalNumber in range(numberOfPetals):
      flower.begin_fill()
      flower.color("white",colors[petalNumber%8])
      draw_square(flower)
      flower.end_fill()
      flower.right(360.0/numberOfPetals)

   window.exitonclick() #when clicked the window closes

#function for original art(which is just stars)
def originalStars(n):

   window = turtle.Screen()
   window.bgcolor("white")
   window.title("Star Power")

   star_spiral = turtle.Turtle()
   star_spiral.begin_fill()
   star_spiral.shape("triangle")
   star_spiral.color("teal")
   for count in range(20+n):
   star_spiral.forward(count*15)
   star_spiral.right(144)
   star_spiral.end_fill()
   window.exitonclick()

#let the user choose
print("Choose from the following:")
print("1. Flowers.")
print("2. Colorful Flower.")
print("3. Spiraled Star.")
UserChoice = int(input())

#if statement check the user choice
if (UserChoice == 1):
   numberOfPetals= int(input("How many petals?"))
#the next line calls the draw flower function
   draw_flower(numberOfPetals)
#elif- chapter 5 conditional statement
elif(UserChoice == 2):
   numberOfPetals = int(input("How many petals?"))
   colorfulArt(numberOfPetals) #this line calls the colorful art function
else:
   (UserChoice == 3)
   numberOfPetals= int(input("How many stars should overlap?"))
   originalStars(numberOfPetals) #this line calls the original stars 
function

Answer 1

我注意到的一个问题是你的陈述

flower="teal"

。通过这样做，您已将

flower

对象（变量）转换为字符串而不是海龟对象，因此此后的其余代码将失败。

下面的代码对我有用：

import sys
import turtle


def draw_square(square):
    for i in range(0, 2):
        square.forward(100)
        square.right(70)
        square.forward(100)
        square.right(110)


def draw_flower(petal_number: int):
    """
    Draws a flower on the screen with a given number of petals
    :param petal_number: 
    :return: Blocks until the user clicks on the screen
    """
    window = turtle.Screen()
    window.bgcolor("beige")
    window.title("Flower")

    flower = turtle.Turtle()
    flower.shape("triangle")
    flower.color("teal")
    flower.pencolor("beige")
    flower.pensize(3)

    flower.goto(15,70)

    for number in range(0, petal_number):
        flower.begin_fill()
        draw_square(flower)
        flower.end_fill()
        flower.right(360.0 / petal_number)

    window.exitonclick()


if __name__ == "__main__":
    draw_flower(3)

Answer 2

最好的花店在木尔坦。