为什么这个laravel集合不能按时间对索引进行排序？

Question

我的目标是有选择地过滤出勤列表，按照给定时间段内最早或最晚到达的员工对员工进行排序。我的逻辑是：

• 按每天分组出勤
• 根据参数，使用排序列表上的索引，按早/迟时间对每个出勤情况进行排名
• 将它们的索引相加以找到每种情况下的最高值

现在的问题是，无论使用什么排序算法，相同的出勤率总是带有相同的索引，即最早的总是带有0。对列表进行排序只是将元素直观地推到列表的底部，但它仍然带有0，这使得没有感觉

我原来的代码是

protected function punctualChart ($attendanceCollection, ?string $puncMode) {

        $puncMode = $puncMode?? "ear";
// group them into each day. rank by employee with most days
        $attendanceDays = $attendanceCollection->groupBy(function ($attendance) {

            return $attendance->created_at->format("m-d");
        })
        ->map(function ($daysCollection) use ($puncMode) { // then sum their value for each day? add their indexes. depending on the mode, we know whether highest or lowest is the winner

            return $daysCollection->sort(function ($a, $b) use ($puncMode) {

                $date1 = $a->created_at;

                $date2 = $b->created_at;

                if ($puncMode == "lat") {

                    if ($b > $a) return 1;

                    if ($a > $b) return -1;

                    return 0;
                }
                else {

                    if ($a > $b) return 1;

                    if ($b > $a) return -1;

                    return 0;
                }
            });
        })->values();
// dd($attendanceDays->get(1), $attendanceDays->get(2), $puncMode);
        $scoreEmployee = [];

        foreach ($attendanceDays as $attendanceCollection) {

            foreach ($attendanceCollection as $index => $attendance) {
dump($index);
                $employeeId = /*$attendance->employee->last_name.*/$attendance->employee_id;

                if (!array_key_exists($employeeId, $scoreEmployee))

                    $scoreEmployee[$employeeId] = /*0;*/[

                        "value" => 0,

                        "model" => $attendance->employee->last_name
                    ];

                $scoreEmployee[$employeeId]["value"] += $index+1; // offset 0-based index
            }
        }

        $sortedEmployeeScores = \Illuminate\Support\Arr::sort($scoreEmployee, "value");
dd($scoreEmployee, $sortedEmployeeScores);
        return $scoreEmployee;
    }

随后被简化为

protected function punctualChart ($attendanceCollection, ?string $puncMode) {

        $puncMode = $puncMode?? "ear";
// group them into each day. rank by employee with most days
        $attendanceDays = $attendanceCollection->groupBy(function ($attendance) {

            return $attendance->created_at->format("m-d");
        })
        ->map(function ($daysCollection) use ($puncMode) { // then sum their value for each day? add their indexes. depending on the mode, we know whether highest or lowest is the winner

            return $puncMode == "ear"? $daysCollection->sortBy("created_at"):

            $daysCollection->sortByDesc("created_at");
        })/*->values()*/;
// dd($attendanceDays->get(1), $attendanceDays->get(2), $puncMode);
        $scoreEmployee = [];

        foreach ($attendanceDays as $attendanceCollection) {

            foreach ($attendanceCollection as $index => $attendance) {
dump($index);
                $employeeId = /*$attendance->employee->last_name.*/$attendance->employee_id;

                if (!array_key_exists($employeeId, $scoreEmployee))

                    $scoreEmployee[$employeeId] = /*0;*/[

                        "value" => 0,

                        "model" => $attendance->employee->last_name
                    ];

                $scoreEmployee[$employeeId]["value"] += $index+1; // offset 0-based index
            }
        }

        $sortedEmployeeScores = \Illuminate\Support\Arr::sort($scoreEmployee, "value");
dd($scoreEmployee, $sortedEmployeeScores);
        return $scoreEmployee;
    }

从那里我意识到排序是不必要的。有趣的是，结果是自动排序的。但是，该索引是固定的并且无法更改。无论情况如何，相同的元素始终具有相同的索引。所以我想也许，反转列表会有所帮助，即我不会传递

puncMode

，而是反转数组以获得逆数组。但这也行不通

那么我做错了什么以及如何交换他们的索引以反映他们的位置？然后将这个位置求和以在我的图表上渲染（您不需要添加这部分。只是为了完成而显示）？

Answer 1

问题似乎在于您在考勤集合迭代期间如何处理索引。通过 foreach 循环获得的索引对应于原始集合中元素的位置，不一定反映排序后您期望的顺序。

您可以应用的解决方案是在排序后重新分配索引，以便它们反映每个考勤的新位置。这里有一个简单的修复方法：

对出勤进行分组和排序后，将索引重新分配给结果集合。确保索引反映新顺序，无论是按最早还是最晚排序。