如何使用Enum将Json反序列化为Java对象?

问题描述 投票:0回答:2

我有以下json我想要反序列化为Java对象:

{
"firstname": "John",
"lastname": "Do",
"sex": "",

}

在另一部分我有一个Java Rest Webservice:

@POST
@Consumes(APPLICATION_JSON)
@Produces(APPLICATION_JSON)
public Response findPerson(@Valid PersonneRequest personne) {

    if(personne!= null){
       Personne result = null;
      // do some stuff 

        return Response.ok(result).build();
    }

    // Bad request
    return Response.status(Response.Status.BAD_REQUEST).build();


}

这是Personne类:

public class PersonneRequest实现Serializable {

private String firstname;

private String lastname;

private Sex sex;

// getter和setter

}

这是我的Sexe课程:

public enum Sex{


    MAN("man"),
    WOMAN("woman");

    private String type;

    private Sex(String type){
        this.type = type;
    }

    public String getType(){
        if(type!=null && !StringUtils.isEmpty(type)){
            return type;
        }
        return MAN.getType();
    }
}

我的问题是当我在我的webervice上打一个电话。当性别空虚时,Json数据不会反序列化。我收到以下异常。如何为枚举的空值设置一个值?这是我的java异常:

org.codehaus.jackson.map.JsonMappingException: Can not construct instance of Sex from String value '': value not one of declared Enum instance names
 at [Source: org.glassfish.jersey.message.internal.EntityInputStream@5ed82ec0; org.codehaus.jackson.map.JsonMappingException.from(JsonMappingException.java:163) ~[jackson-mapper-asl-1.9.2.jar:1.9.2]
    at org.codehaus.jackson.map.deser.StdDeserializationContext.weirdStringException(StdDeserializationContext.java:243) ~[jackson-mapper-asl-1.9.2.jar:1.9.2]
    at org.codehaus.jackson.map.deser.std.EnumDeserializer.deserialize(EnumDeserializer.java:74) ~[jackson-mapper-asl-1.9.2.jar:1.9.2]
    at org.codehaus.jackson.map.deser.std.EnumDeserializer.deserialize(EnumDeserializer.java:23) ~[jackson-mapper-asl-1.9.2.jar:1.9.2]
    at org.codehaus.jackson.map.deser.SettableBeanProperty.deserialize(SettableBeanProperty.java:299) ~[jackson-mapper-asl-1.9.2.jar:1.9.2]
    at org.codehaus.jackson.map.deser.SettableBeanProperty$MethodProperty.deserializeAndSet(SettableBeanProperty.java:414) ~[jackson-mapper-asl-1.9.2.jar:1.9.2]
    at org.codehaus.jackson.map.deser.BeanDeserializer.deserializeFromObject(BeanDeserializer.java:697) ~[jackson-mapper-asl-1.9.2.jar:1.9.2]
    at org.codehaus.jackson.map.deser.BeanDeserializer.deserialize(BeanDeserializer.java:580) ~[jackson-mapper-asl-1.9.2.jar:1.9.2]
    at org.codehaus.jackson.map.ObjectMapper._readValue(ObjectMapper.java:2695) ~[jackson-mapper-asl-1.9.2.jar:1.9.2]
    at org.codehaus.jackson.map.ObjectMapper.readValue(ObjectMapper.java:1308) ~[jackson-mapper-asl-1.9.2.jar:1.9.2]
    at org.codehaus.jackson.jaxrs.JacksonJsonProvider.readFrom(JacksonJsonProvider.java:419) ~[jackson-jaxrs-1.9.13.jar:1.9.13]

谢谢

java json serialization enums
2个回答
0
投票

将@JsonInclude(JsonInclude.Include.NON_EMPTY)与属性Sex一起使用。它将处理空字符串值。

@JsonInclude(JsonInclude.Include.NON_EMPTY)
private Sex sex;

我希望这可以帮到你。


0
投票

我认为您的代码中存在两个问题:首先,类enum Sex中的getType()方法是错误的。返回MAN.getType()表示调用本身,以便导致不定式循环。可能是你想要捕获为枚举分配null但不是正确方法的情况。

其次,与日志文件中的问题直接相关的原因是不能为枚举类型分配null或空值。我认为使用@JsonIgnoreProperties和DeserializationFeature.READ_UNKNOWN_ENUM_VALUES_AS_NULL是解决问题的最佳方法请参考这里的帖子:How to ignore enum fields in Jackson JSON-to-Object mapping?

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