任何人都可以发现这段代码中的错误在哪里，当我选择不再玩时它会陷入无限循环吗？

Question

import random

random_num = random.randint(1, 100)

count = 1
while True:
    try:
        num = int(input("Guess the number? "))

        if num == random_num:
            print("Congrates! you guessed it.")
            print("Tried:", count, "times")

            play = input("Do you want to play again Y/N? ")
            if play.lower() in ['n', 'no']:
                quit()

            elif play.lower() in ['y', 'yes']:
                random_num = random.randint(1, 100)
                count = 1

            else:
                quit()

        elif num > random_num:
            print("Not yet, smaller.")
        elif num < random_num:
            print("Not yet, Greater.")
        else:
            quit()
        count += 1
    except:
        print("Oops! please enter a valid number.")

当我运行此代码时，它运行正常。但是当我完成游戏并选择不再玩时，它陷入了无限循环

当我运行好并选择 n 或 no 时，它陷入无限循环

Guess the number? Oops! please enter a valid number.

永远，但我期待的是完成游戏并结束程序。

Answer 1

正如@Cincinnatus 评论的那样，使用

break

语句退出循环应该可以解决这个问题。或者，您可以尝试建立一个变量来维护循环的当前“运行”状态。这是调整为使用此模式的代码：

import random

random_num = random.randint(1, 100)

count = 1
running = True
while running:
    try:
        num = int(input("Guess the number? "))

        if num == random_num:
            print("Congrates! you guessed it.")
            print("Tried:", count, "times")

            play = input("Do you want to play again Y/N? ")
            if play.lower() in ['n', 'no']:
                running = False

            elif play.lower() in ['y', 'yes']:
                random_num = random.randint(1, 100)
                count = 1

            else:
                running = False

        elif num > random_num:
            print("Not yet, smaller.")
        elif num < random_num:
            print("Not yet, Greater.")
        else:
            running = False
        count += 1
    except:
        print("Oops! please enter a valid number.")