嗨我正在尝试Http Post请求,但收到错误请求的错误我认为我在请求中做错了,如果任何人可以帮助我。
这是请求
POST /uapi/faxes/@me/0003*210 HTTP/1.1
HOST uapi.voipnow.com
Content-Length:469
Content-Type: multipart/form-data; boundary=------------325343636
------------325343636--------
Content-Disposition:form-data; name="files"; filename="/path/to/file/fax.txt"
Content-Type;application/octet-stream
This is my fax
------------325343636
Content-Disposition:form-data; name="request";
{
"recipients":["7778888"]
}
------------3253436360
这是我的此请求的代码
try
{
String Token = "mytoken";
ServicePointManager.ServerCertificateValidationCallback = new RemoteCertificateValidationCallback(delegate { return true; });
HttpWebRequest httpWReq2 = (HttpWebRequest)WebRequest.Create("https://domainname/uapi/faxes/@me/0014*100/?accessRequestToken=" + Token);
ASCIIEncoding encoding2 = new ASCIIEncoding();
string postData2 =
"------------325343636" + Environment.NewLine +
"Content-Disposition:form-data; name=\"files\";filename=\"/path/to/file/fax.txt\";" + Environment.NewLine +
"Content-Type:application/octet-stream;" + Environment.NewLine +
"This is my fax" + Environment.NewLine +
"------------325343636" + Environment.NewLine +
"Content-Disposition:form-data; name=\"request\";" + Environment.NewLine +
"{" + Environment.NewLine +
"\"recipients\":[\"111111\"];" + Environment.NewLine +
"}" + Environment.NewLine +
"------------325343636";
byte[] data2 = encoding2.GetBytes(postData2);
httpWReq2.Method = "POST";
httpWReq2.ContentType = "multipart/form-data; boundary=------------325343636";
httpWReq2.KeepAlive = true;
httpWReq2.UserAgent = "Mozilla/5.0 (Windows NT 5.1) AppleWebKit/537.17 (KHTML, like Gecko) Chrome/24.0.1312.52 Safari/537.17";
httpWReq2.ContentLength =data2.Length;
httpWReq2.Host = "hostname";
string result2 = "";
Stream dataStream2 = httpWReq2.GetRequestStream();
dataStream2.Write(data2, 0, data2.Length);
dataStream2.Close();
WebResponse response2 = httpWReq2.GetResponse();
HttpWebResponse responce3 = (HttpWebResponse)httpWReq2.GetResponse();
dataStream2 = response2.GetResponseStream();
// Open the stream using a StreamReader for easy access.
StreamReader reader2 = new StreamReader(dataStream2);
// Read the content.
string responseFromServer2 = reader2.ReadToEnd();
}
catch (Exception ex)
{
WebException ex2 = (WebException)ex;
if (ex2.Status == WebExceptionStatus.ProtocolError)
{
WebResponse resp = ex2.Response;
using (Stream respstream = resp.GetResponseStream())
{
StreamReader reader = new StreamReader(respstream);
String finalerror = reader.ReadToEnd();
}
}
}
错误
“收件人”参数中提供的值缺失或无效。该参数必须引用任何电话号码
哦,我发现了一个潜在的问题。看起来您正在发送JSON对象而不是表单编码值。
------------325343636
Content-Disposition:form-data; name="request";
recipients=7778888
------------3253436360
尝试这些方面的东西。
你的界限不匹配。
POST /uapi/faxes/@me/0003*210 HTTP/1.1
HOST uapi.voipnow.com
Content-Length:469
Content-Type: multipart/form-data; boundary=------------325343636
--------------325343636
Content-Disposition:form-data; name="files"; filename="/path/to/file/fax.txt"
Content-Type;application/octet-stream
This is my fax
--------------325343636
Content-Disposition:form-data; name="request";
{
"recipients":["7778888"]
}
--------------325343636--
你的边界应该是 - (两个连字符)+你的边界。最后一个边界应遵循相同的公式,并在末尾添加 - (两个连字符)。
在您的示例中,您的结束边界不同,并且在边界前面没有额外的两个连字符。
为了澄清一点,如果你的边界是“边界”,它将是这样的:
POST /uapi/faxes/@me/0003*210 HTTP/1.1
HOST uapi.voipnow.com
Content-Length:469
Content-Type: multipart/form-data; boundary=a boundary
--a boundary
Content-Disposition:form-data; name="files"; filename="/path/to/file/fax.txt"
Content-Type;application/octet-stream
This is my fax
--a boundary
Content-Disposition:form-data; name="request";
{
"recipients":["7778888"]
}
--a boundary--