我试图在我的TicTacToe游戏中使用checkgamewinner方法，但我在循环开始或结束时遇到了问题。每当我开始打开我的游戏并点击一个字段时，它就会打印出 "没有赢家"。这是我目前的代码。
public String checkGameWinner(char [][]grid) {
boolean winner = false;
String result = "None";
while(!winner) {
for (int i = 0; i < 3; i++) {
for (int j = 0; j < 3; j++) {
if (gridAt(0, 0) == 'x' & gridAt(0, 1) == 'x' & gridAt(0, 2) == 'x') {
winner = true;
System.out.println("Player x has won");
break;
} else if (gridAt(0, 0) == 'x' & gridAt(1, 0) == 'x' & gridAt(2, 0) == 'x') {
winner = true;
System.out.println("Player x has won");
break;
} else if (gridAt(0, 0) == 'x' & gridAt(1, 1) == 'x' & gridAt(2, 2) == 'x') {
winner = true;
System.out.println("Player x has won");
break;
} else if (gridAt(1, 0) == 'x' & gridAt(1, 1) == 'x' & gridAt(1, 2) == 'x') {
winner = true;
System.out.println("Player x has won");
break;
} else if (gridAt(2, 0) == 'x' & gridAt(2, 1) == 'x' & gridAt(2, 2) == 'x') {
winner = true;
System.out.println("Player x has won");
break;
} else if (gridAt(0, 1) == 'x' & gridAt(1, 1) == 'x' & gridAt(2, 1) == 'x') {
winner = true;
System.out.println("Player x has won");
break;
} else if (gridAt(0, 2) == 'x' & gridAt(1, 2) == 'x' & gridAt(2, 2) == 'x') {
winner = true;
System.out.println("Player x has won");
break;
} else if (gridAt(0, 2) == 'x' & gridAt(1, 1) == 'x' & gridAt(2, 0) == 'x') {
winner = true;
System.out.println("Player x has won");
break;
} else if (gridAt(0, 0) == 'x' & gridAt(0, 1) == 'x' & gridAt(0, 2) == 'x') {
winner = true;
System.out.println("Player x has won");
break;
} else if (gridAt(0, 0) == 'o' & gridAt(1, 0) == 'o' & gridAt(2, 0) == 'o') {
winner = true;
System.out.println("Player o has won");
} else if (gridAt(0, 0) == 'o' & gridAt(1, 1) == 'o' & gridAt(2, 2) == 'o') {
winner = true;
System.out.println("Player o has won");
} else if (gridAt(1, 0) == 'o' & gridAt(1, 1) == 'o' & gridAt(1, 2) == 'o') {
winner = true;
System.out.println("Player o has won");
} else if (gridAt(2, 0) == 'o' & gridAt(2, 1) == 'o' & gridAt(2, 2) == 'o') {
winner = true;
System.out.println("Player o has won");
} else if (gridAt(0, 1) == 'o' & gridAt(1, 1) == 'o' & gridAt(2, 1) == 'o') {
winner = true;
System.out.println("Player o has won");
} else if (gridAt(0, 2) == 'o' & gridAt(1, 2) == 'o' & gridAt(2, 2) == 'o') {
winner = true;
System.out.println("Player o has won");
} else if (gridAt(0, 2) == 'o' & gridAt(1, 1) == 'o' & gridAt(2, 0) == 'o') {
winner = true;
System.out.println("Player o has won");
} else {
result = "no winner";
System.out.println(result);
}
}
}
}
return result;
}
我不知道我还能做什么，我用booleans玩了一下，但当我的棋盘上有赢家时，它就不会停止......我希望有人能帮我一下，谢谢!
你不需要同时使用循环和if else条件。我已经创建了带有if else条件的示例程序。
public class Main
{
public static void main(String[] args) {
char [][]grid = {
{'x', 'x', 'x'},
{'x', 'x', 'x'},
{'x', 'x', 'x'}
};
checkGameWinner(grid);
}
public static String checkGameWinner(char [][]grid) {
String result = "None";
boolean winner = true;
if (grid[0][0] == 'x' && grid[0][1] == 'x' && grid[0][2] == 'x') {
result = "Player x has won";
} else if (grid[0][0] == 'x' && grid[1][0] == 'x' && grid[2][0] == 'x') {
result = "Player x has won";
} else if (grid[0][0] == 'x' && grid[1][1] == 'x' && grid[2][2] == 'x') {
result = "Player x has won";
} else if (grid[1][0] == 'x' && grid[1][1] == 'x' && grid[1][2] == 'x') {
result = "Player x has won";
} else if (grid[2][0] == 'x' && grid[2][1] == 'x' && grid[2][2] == 'x') {
result = "Player x has won";
} else if (grid[0][1] == 'x' && grid[1][1] == 'x' && grid[2][1] == 'x') {
result = "Player x has won";
} else if (grid[0][2] == 'x' && grid[1][2] == 'x' && grid[2][2] == 'x') {
result = "Player x has won";
} else if (grid[0][2] == 'x' && grid[1][1] == 'x' && grid[2][0] == 'x') {
result = "Player x has won";
} else if (grid[0][0] == 'x' && grid[0][1] == 'x' && grid[0][2] == 'x') {
result = "Player x has won";
} else if (grid[0][0] == 'o' && grid[1][0] == 'o' && grid[2][0] == 'o') {
result = "Player o has won";
} else if (grid[0][0] == 'o' && grid[1][1] == 'o' && grid[2][2] == 'o') {
result = "Player o has won";
} else if (grid[1][0] == 'o' && grid[1][1] == 'o' && grid[1][2] == 'o') {
result = "Player o has won";
} else if (grid[2][0] == 'o' && grid[2][1] == 'o' && grid[2][2] == 'o') {
result = "Player o has won";
} else if (grid[0][1] == 'o' && grid[1][1] == 'o' && grid[2][1] == 'o') {
result = "Player o has won";
} else if (grid[0][2] == 'o' && grid[1][2] == 'o' && grid[2][2] == 'o') {
result = "Player o has won";
} else if (grid[0][2] == 'o' && grid[1][1] == 'o' && grid[2][0] == 'o') {
result = "Player o has won";
} else {
result = "no winner";
winner = false;
}
System.out.println(result);
return result;
}
}
注意：以上不是解决这个问题的最好方法。 以上并不是解决这个问题的最佳方法。
为什么不使自己更容易，并创建这样的方法。
private boolean checkRows() {
}
private boolean checkColumns() {
}
private boolean checkDiagnonals() {
}
这样的话，每个方法中的测试次数就会减少，而且它们作为单独的方法可以更容易地进行调试。
if (checkRows() || checkColumns() || checkDiagonals()) {
// winning code here.
}
我假设它们是实例方法，所以它们可以访问到 char[][] grid.
关于你现在的代码。
return true.return false.为了调试，建立两个测试用例 x 和 o 所以你知道该去哪里找
我没有检查过你的逻辑，但从我的观察来看，你提到的问题是因为当你打开游戏的时候，你的格子会完全是空的，因此它会转到 else 块来执行。
希望能给你指引正确的方向，如何正确的写逻辑。
另外，尽量把你的方法正确的划分，这样才容易阅读、调试和维护。
祝你学习愉快!