当我想在标记的列上应用函数时,出现以下错误。作为示例,我应用了 mean() 函数。
library(tidyr)
library(dplyr)
library(Hmisc)
df <- data.frame(a = LETTERS[1:5],
b = c(1,2,NA,4,5))
Hmisc::label(df$a) <- "hi hi"
Hmisc::label(df$b) <- "bye bye"
names(df) <- Hmisc::label(df)
df %>%
mutate(`hi hi` = paste0(`hi hi`, "people"),
`bye bye` = replace_na(`bye bye`, mean(`bye bye`, na.rm = T)))
#mean(df$`bye bye`, na.rm = T)
错误是:
Error in `mutate()`:
ℹ In argument: `bye bye = replace_na(`bye bye`, mean(`bye bye`, na.rm = T))`.
Caused by error in `vec_assign()`:
! Can't convert `replace` <double> to match type of `data` <labelled>.
Backtrace:
1. df %>% ...
10. tidyr:::replace_na.default(`bye bye`, mean(`bye bye`, na.rm = T))
11. vctrs::vec_assign(data, missing, replace, x_arg = "data", value_arg = "replace")
Error in mutate(., `hi hi` = paste0(`hi hi`, "people"), `bye bye` = replace_na(`bye bye`, :
Caused by error in `vec_assign()`:
! Can't convert `replace` <double> to match type of `data` <labelled>.
类型好像和
replace_na
冲突;这里bye bye
可能需要是数字:
library(dplyr)
df |>
mutate(`hi hi` = paste0(`hi hi`, "people"),
`bye bye` = as.numeric(`bye bye`),
`bye bye` = replace_na(`bye bye`, mean(`bye bye`, na.rm = T)))
但是您也可以考虑采用
base
方式:
is.na(df$`bye bye`) <- mean(df$`bye bye`, na.rm = TRUE)
输出:
hi hi bye bye
1 Apeople 1
2 Bpeople 2
3 Cpeople 3
4 Dpeople 4
5 Epeople 5