如何在SQL Server中使用逗号汇总数字？

Question

我有字符串字段像（1100,2014,4000）我想分开逗号并将每个数字彼此相加，例如：1100,2014,4000

1 1 0 0
2 0 1 4 
4 0 0 0

结果

@first =1+2+4=7 
@second= 1+0+0=1
@third=0+1+0=1
@forth=0+4+0=4

Answer 1

试试这个，

DECLARE @Table TABLE(Value VARCHAR(20))
 INSERT INTO @Table VALUES('1100,2014,4000')

 DECLARE @First INT, @Second INT, @Third INT, @Fourth INT

SELECT Split.a.value('.', 'VARCHAR(100)') AS Data  
INTO #temp
FROM  
(
    SELECT CAST ('<M>' + REPLACE(Value, ',', '</M><M>') + '</M>' AS XML) AS Value  
    FROM  @Table
) AS A CROSS APPLY Value.nodes ('/M') AS Split(a); 


SELECT @First=SUM(Data/1000)
    ,@Second=SUM((Data%1000)/100)
    ,@Third=SUM((Data%100)/10)
    ,@Fourth=SUM((Data%10))
FROM #temp

SELECT @First, @Second, @Third, @Fourth

DROP TABLE #temp

Answer 2

这可能有助于获得如下值的总和：

SELECT  SUM(CAST(SUBSTRING(X.A, 1, 1) AS INT)) first,
    SUM(CAST(SUBSTRING(X.A, 2, 1) AS INT)) second,
    SUM(CAST(SUBSTRING(X.A, 3, 1) AS INT)) third,
    SUM(CAST(SUBSTRING(X.A, 4, 1) AS INT)) fourth
FROM    ( SELECT    '1100' A
      UNION
      SELECT    '2014' A
      UNION
      SELECT    '4000' A
    ) X

Answer 3

以下带有多个SQL CTE表达式的Select语句可以在numbers table function和SQL split string function的帮助下使用“，”作为分隔符来分割数字列表

为了进一步将每个数字拆分成数字，我更喜欢使用子串函数

with cte as (
    select
    *
    from NumbersList n,
    dbo.NumbersTable(1,4,1) as nt 
), splitted as (
select
    list,
    id,
    i,
    substring(val,i,1) val
from cte
cross apply dbo.Split(list,',') v
)
select
    distinct
    list,
    i,
    sum(cast(val as int)) over (partition by list, i) sumOf
from splitted

以下条目的输出

insert into NumbersList select '1100,2014,4000'
insert into NumbersList select '1111,2222,3456'

如下

Answer 4

首先，使用Jeff Moden的DelimitedSplit8K（因为我不知道您使用的是什么版本的SQl服务器）。其次，你的逻辑似乎有些偏差。你说你的变量@third的值是0+4+0，但是，这是整数的第四个字符。此外，这假设所有整数都是4个字符长。

WITH VTE AS(
    SELECT *
    FROM (VALUES('1100,2014,4000')) v(DSn)) --This is your samnple data 
SELECT SUM(CONVERT(int,SUBSTRING(RIGHT('0000' + DS.Item,4),N.I, 1))) AS [Sum]
FROM VTE
     CROSS APPLY dbo.DelimitedSplit8K (VTE.DSn,',') DS
     CROSS APPLY (VALUES (1),(2),(3),(4)) N(I)
GROUP BY N.I;

Answer 5

您可以将此函数用于表中的所有项目行。

你可以创建这个函数然后尝试从dbo.string2table（'1243,1234,2343'，'，'）中选择*

CREATE FUNCTION [dbo].[string2table]
(
    @string VARCHAR(MAX),
    @delimiter CHAR(1)
)
RETURNS @output TABLE(
    data VARCHAR(256)
)
BEGIN

    DECLARE @start INT, @end INT
    SELECT @start = 1, @end = CHARINDEX(@delimiter, @string)

    WHILE @start < LEN(@string) + 1 BEGIN
        IF @end = 0 
            SET @end = LEN(@string) + 1

        INSERT INTO @output (data) 
        VALUES(SUBSTRING(@string, @start, @end - @start))
        SET @start = @end + 1
        SET @end = CHARINDEX(@delimiter, @string, @start)
    END

    RETURN

END