如何回显.txt的位置？

Question

我正在做一个基于两个.txt的代码，一个带有名字，另一个带有生日。我正在阅读它们，当日期与date.txt重合时，将显示names.txt的重合行中的名称，但是当我进行比较时，只显示names.txt的最后一行。

那是代码：

<?php

    $nome   =   fopen("nome.txt", "r");
    while(!feof($nome)){
        $pessoa =   fgets($nome);
    }   fclose($nome);

    $current    =   date("d-m");
    $content    =   fopen("data.txt", "r");

    while (!feof($content)){
        $linha  = fgets($content);
        if (strtotime($linha)   ==  strtotime($current))   {
            echo $pessoa;
            echo '<br>';
        }
    }   fclose($content);

    ?>

.txt的内容：

---

nome.txt：

测试

teste1

teste2

照

---

data.txt中：

12-12

18-12

12-12

12-12

Answer 1

您可以同时从两个文件中逐行处理

<?php

    $nome    =   fopen("nome.txt", "r");
    $content =   fopen("data.txt", "r");
    $current =   date("d-m");

    while(!feof($nome) && !feof($content)){
        $pessoa =   fgets($nome);
        $linha  = fgets($content);

        if (trim($current) == trim($linha))   {
            echo $pessoa;
            echo '<br>';
        }
    }   

    fclose($content);
    fclose($nome);

?>

或者您可以使用file function将整个文件读入数组，但这可能会更慢

<?php

    $nome    =   file("nome.txt");
    $content =   file("data.txt");
    $current =   date("d-m");

    foreach($content as $key => $linha)

        if (trim($current) == trim($linha))   {
            echo $nome[$key];
            echo '<br>';
        }

?>

Answer 2

您可以打开文件并将它们加载到数组中，并使用foreach和$ key同步输出它们。

$names = explode(PHP_EOL,file_get_contents("none.txt"));

$dates = explode(PHP_EOL,file_get_contents("data.txt"));

Foreach($names as $key => $name){

     Echo $name . " " . $dates[$key] . "\n";
}

https://3v4l.org/59ao6

另一种方法是将两个数组合并为一个。 但是这有一个缺陷，你不能有两个同名的人。

$days = array_combine($names, $dates);
// Days is now an associate array with name as key and date as birthday.
Foreach($days as $name => $date){

     Echo $name . " " . $date . "\n";
}