我如何使用HTTP:PostAsync()将JSON数据提交到服务器? (ROBLOX)

问题描述 投票:0回答:1

因此,我了解GetAsync的工作原理,并且服务器上具有可以与我要完成的工作一起工作的脚本。但是就将数据获取到服务器而不是从json读取数据而言,我该怎么做?在服务器端,我的PHP脚本从提交的JSON获取所有发布数据,并检查包含所有信息的数据库,如果不存在,则将其插入。 (这是一个禁令系统。但是我不确定我是否正确设置了roblox端,或者我是否正确设置了服务器端。这是我的代码:

这正在Custom Adonis管理系统中运行

SendWebBan = function(plr,UserID,Username,Agent,Comment)
            local http = game:GetService("HttpService")
            local Reason = "Banned in game by AAC Admin."
            local url = "URL HERE/gamebanlistener.php"
            local data = {
                ["UserID"] = UserID,
                ["Username"] = Username,
                ["Agent"] = Agent,
                ["Reason"] = Reason,
                ["Comment"] = Comment
            }

            local encode = http:JSONEncode(data)


            local reponse,err = pcall(function()
                http:PostAsync(url,encode)
            end)

            print(reponse)

            if reponse == "false" then
                Remote.MakeGui(plr,"Notification",{
                    Title = "Failed";
                    Message = "Ban Failed";
                    Duration = 10;
                })
            elseif reponse == "true" then
                Remote.MakeGui(plr,"Notification",{
                    Title = "Success";
                    Message = "Ban Successful";
                    Duration = 10;
                })
            else
                Remote.MakeGui(plr,"Notification",{
                    Title = "Failed";
                    Message = "Ban Failed";
                    Duration = 10;
                })
            end
        end;
<?php
    $ServerKey = "key here";
    $APIKey = $_POST["key"];
    $Data = json_decode($_POST['data']);
    $UserID = $Data.UserID;
    $Username = $Data.Username;
    $Agent = $Data.Agent;
    $Reason = $Data.Reason;
    $Comment = $Data.Comment;

    $Date = date("d/m/Y");
    if($APIKey == $ServerKey){
       //$conn = mysqli_connect($host,$dbuser,$dbpassword,$db);
        $Connection = mysqli_connect(sql credentials here);

    if($Connection->connect_errno)
    {
        echo('{"Status":"'. $Connection->connect_errno . '"}');
    }else {
        $BlacklResult = $Connection->query("SELECT * FROM bans"); //Blacklist is the name of my Bans database

        if($BlacklResult->num_rows > 0)
        {
            while($Row = $BlacklResult->fetch_assoc()){
                if($Row != null){
                    if($Row["UserID"] == $UserID){
                     echo 'Status:false';
                     return;
                    }else{
                     $Connection->query("INSERT INTO bans(UserID, Username, Agent, BanReason, BanComment,DateOfBan) VALUES(".$UserID.",".$Username.",".$Agent.",".$Reason.",".$Comment.",".$Date.");");
                     echo 'Status:true';
                    }
                };
            };
        };

        };
    }else {
        echo('{"Status":"API KEY"}');
    };
?>
php lua roblox
1个回答
0
投票

当您调用一个函数时,返回的元组是一个布尔值,后跟该函数的结果。如果函数抛出错误,则结果将替换为错误字符串。尝试进行此更改:

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