listagg函数没有group by

Question

我在select语句中有很多列，其中许多是派生计算。

我试图在listagg()语句中使用select将多行组合成一行，但不必在group by语句中使用select其余列。沿着listagg() within group() over (partition by id)的路线。

现在我有一些东西：

select id, listagg(distinct annual_bill_rate, ', ') within group (order by bill_rate) as annual_bill_rate, email, state
from table
group by 1,3,4

根据文档，似乎没有可能避免这个群体，但有其他选择吗？我有30多列，我不能将它们全部分组。谢谢！

样本数据：

id   bill_rate   email        state 
1    0.0035      [email protected]  NJ
1    0.0045      [email protected]  NJ
1    0.0055      [email protected]  NJ
2    0.0065      [email protected]  NY
2    0.0075      [email protected]  NY
3    0.0085      [email protected]  PA

期望的结果 - 没有GROUP BY：

id   bill_rate                email        state 
1    0.0035, 0.0045, 0.0055   [email protected]  NJ
2    0.0065, 0.0075           [email protected]  NY
3    0.0085                   [email protected]  PA

Answer 1

避免键入GROUP BY这是一个不太好的主意。它几乎肯定会变慢，而且阅读和理解起来要困难得多。如果我在生产代码中碰到这个，我会是一个不快乐的家伙：

WITH table_distinct AS 
(
    SELECT DISTINCT id, email, state
    FROM table
)
,table_group_by AS
(
    SELECT id, listagg(distinct annual_bill_rate, ', ') within group (order by bill_rate) as annual_bill_rate
    FROM table
    GROUP BY id
)
SELECT 
    td.*,
    tgb.annual_bill_rate        
FROM table_distinct td
    INNER JOIN table_group_by tgb
        ON td.id = tgb.id;

现在你真的只需要使用table_distinct CTE的猴子来为你的结果集添加更多的列。