使用一个按钮codeigniter mysql在多个数据库中保存多个值

Question

我是CodeIgniter的新手，仍在学习和探索它。我有这个视图，用户添加类别和大小。它具有大小的无限或动态输入字段，因此如果类别为ex。裤子，裤子有很多尺寸，所以用户只需点击添加更多按钮。但这是我储存所有输入的东西。我想保存类别和类别的相应大小。这是我的桌子

    CREATE TABLE `category` (
  `category_id` int(11) NOT NULL AUTO_INCREMENT,
  `category_name` varchar(55) NOT NULL,
  PRIMARY KEY (`category_id`)
) ENGINE=InnoDB AUTO_INCREMENT=12 DEFAULT CHARSET=latin1;
CREATE TABLE `sizes` (
  `size_id` int(11) NOT NULL AUTO_INCREMENT,
  `size` varchar(45) NOT NULL,
  `category_id` int(11) NOT NULL,
       PRIMARY KEY (`size_id`),
         KEY `cat_fk_idx` (`category_id`),
      CONSTRAINT `cat_fk` FOREIGN KEY (`category_id`) REFERENCES `category` 
        (`category_id`) 
             ) 

这是我的观点.php

<div class="col-sm-5">
<?php echo $this->session->flashdata('errorMessage');?>
<?php echo $this->session->flashdata('successMessage');?>
<?php echo form_open('category_con/add_category'); ?>
<?php echo form_fieldset('<h1 class="text-danger">Categories</h1>'); ?>
<div class="form-group">
    <label for='Username'>Add New Category</label>
    <input type="text" name="category_name" class="form-control" placeholder="Add new Category here">
</div>

<script src="assets/js/jquery.min.js"></script>         
                <div class="form-group">  
                     <form name="add_name" id="add_name">  
                          <div class="table-responsive">  
                               <table class="table table-bordered" id="dynamic_field">  
                                    <tr>  
                                         <td><input type="text" name="name[]" placeholder="Add Size" class="form-control name_list" /></td>  
                                         <td><button type="button" name="add" id="add" class="btn btn-success">Add More</button></td>  
                                    </tr>  
                               </table>  

                          </div>  
                     </form>  
                </div>  
  <div class="form-group">
    <input type="submit" name="save_category" class="btn btn-success" value="Save Category">
</div>           
</div>  

 <script>  
 $(document).ready(function(){  
      var i=1;  
      $('#add').click(function(){  
           i++;  
           $('#dynamic_field').append('<tr id="row'+i+'"><td><input type="text" name="name[]" placeholder="Add Size" class="form-control name_list" /></td><td><button type="button" name="remove" id="'+i+'" class="btn btn-danger btn_remove">X</button></td></tr>');  
      });  
      $(document).on('click', '.btn_remove', function(){  
           var button_id = $(this).attr("id");   
           $('#row'+button_id+'').remove();  
      });  
      $('#submit').click(function(){            
           $.ajax({  
                url:"name.php",  
                method:"POST",  
                data:$('#add_name').serialize(),  
                success:function(data)  
                {  
                     alert(data);  
                     $('#add_name')[0].reset();  
                }  
           });  
      });  
 });  
 </script>

我希望你能帮助我。谢谢。

Answer 1

创建名为Test.php的模型

<?php

class Test extends CI_Model
{

    public function create()
    {
        $data = array(
           array(
              'category_name' => 'Data Input of category_name' // data input (category_name)
           ),
           array(
              'category_name' => 'Data Input category_name'   // data input (category_name)
           )
        );


        $this->db->insert_batch('category', $data); 

        $last_row_id = $this->db->insert_id();  // Gets last row id ( category_id )

        $data = array(
           array(
                'size'        => 'Data input of size' ,
                'category_id' => $last_row_id
           ),
           array(
                'size'        => 'Data input of size' ,
                'category_id' => $last_row_id
           )
        );


        $this->db->insert_batch('sizes', $data);

    }


}

您可以将数据动态传递到模型类中

在控制器的某个地方

$this->load->model('test'); //Model loaded
$this->test->create();     // Insertion happened to multiple tables